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1 year ago

This reaction represents cellular respiration. What happens to the energy released from glucose during this reaction?.

1 answer:

6 0

The energy released from glucose during this reaction is used and also wasted. Some of the energy is used as work while some amounts are used in other processes or stored for transfer to other organisms. Also, some of the energy is wasted in the form of heat.

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Choose ALL of the answers that would support the theory of Continental Drift?

saveliy_v [14]

The answers are B, D, E!

7 0

3 years ago

Read 2 more answers

A heat engine with 0.500 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 700 K . The gas goes through the fo

Zarrin [17]

Answer:

2234.63

Explanation:

Work done per cycle by the engine is calculated as;

$W=\int p \ dv$

#Since volume doesn't change in the isochoric steps, there is no work done, hence:

$W_2=W_3=0$

#For an isothermal change of state(ideal gas):

$pV=nRT\\\\W=P_iV_ i\int \frac{1}{V} \ dV\\\\=P_iV_ iIn(V_f/V_i)$

#for the expansion process:

$W_i=0.5mol\times8.3145J/molK\times 700K \ In(6000cm^3/1000cm^3)\\\\W_i=5214.15J$

$W_4=0.5mol\times8.3145J/molK\times 400K \ In(6000cm^3/1000cm^3)\\\\W_4=-2979.52$

$W=W_1+W_2+W_3+W_4\\\\=5214.15J-2979.52\\\\=2234.63J$

Hence, the engine does 2234.63J per second.

8 0

4 years ago

the cyclist has a mass of 50kg and is acceleratiing at 0.9m/s^2. What is the size of the unbalanced force F acting on the cyclis

stiv31 [10]

Answer:

45 N

Explanation:

The question can be solved by using Newton's second law:

F = ma

where

F is the net (unbalanced) force on the cyclist

m is the mass of the cyclist

a is his acceleration

In this problem:

m = 50 kg

$a=0.9 m/s^2$

Therefore, the unbalanced force is

$F=(50)(0.9)=45 N$

4 0

4 years ago

Follow these steps to solve this problem: Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 m apart and are emitting

horsena [70]

Answer:

Explanation:

Wave length of sound from each of the speakers = 340 / 1700 = .2 m = 20 cm

Distance between first speaker and the given point = 4 m.

Distance between second speaker and the given sound

= √ 4² + 2² = √16 +4 = √20 = 4.472 m

Path difference = 4.472 - 4 = .4722 m.

Path difference / wave length = 0.4772 / 0.2 = 2.386

This is a fractional integer which is neither an odd nor an even multiple of half wavelength. Hence this point of neither a perfect constructive nor a perfect destructive interference.

7 0

3 years ago

A chair of weight 70.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F =

Annette [7]

Answer:

94.67 N

Explanation:

Consider a free body diagram with force, F of 41 N applied at an angle of 37 degrees while the weight acts downwards. Resolving the force into vertical and horizontal components, we obtain a free body diagram attached.

At equilibrium, normal reaction is equal to the sum of the weight and the vertical component of the force applied. Applying the condition of equilibrium along the vertical direction.

$\begin{array}{l}\\\Sigma {F_y} = 0\\\\N - W - F\sin \theta = 0\\\\N = W + F\sin \theta \\\end{array}$

Substituting 70 N for W, 41 N for F and $\theta$ for 37 degrees

N=70+41sin37=94.67441595 N and rounding off to 2 decimal places

N=94.67 N

6 0

4 years ago