The answer is n(9m-17p-2)
So you would first multiply the whole equations by 1/3, that would look like
1*n(-6+27m-51p)/3 that would equal n(-6+27m-51p)/3
In order for you to get it out of fraction mode you have to multiply the numerator and denominator by 3 and then your answer would be n(9m-17p-2).
Answer:
B:
Step-by-step explanation:
brainliest pls
To find the zeros of this equation you need to first set it equal to zero
2x2 + 16x - 9 = 0
But since you can't FOIL this equation you need to move the non-variable number over
2x2 +16x = 9
Now solve for x by pulling an x out of the equation
x(2x + 16) = 9
x = 9
2x +16 = 9
2x = -7
x = -7/2
So your zeros would be at x = 9, and -7/2
Both of your answers are correct!
so yes youre doing it right