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seropon [69]
4 years ago
10

A car rental company charges $31 per day to rent a particular type of car, and $0.19 per mile. Juan is charged $59.31 for a one-

day rental. How many miles did he drive? (Show your algebraic work)
Mathematics
1 answer:
snow_lady [41]4 years ago
5 0

x = # of miles

$59.31 = $31 + $0.19x

Subtract $31 from both sides

$28.31 = $0.19x

Divide both sides by $0.19

149 = x

Juan drove 149 miles

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The average full-time faculty member in a college works an average of 53 hours per week. a) If we assume the standard deviation
arsen [322]

Answer:

2.28% of faculty members work more than 58.6 hours a week.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The average full-time faculty member in a college works an average of 53 hours per week. Standard deviation of 2.8 hours.

This means that \mu = 53, \sigma = 2.8

What percentage of faculty members work more than 58.6 hours a week?

The proportion is 1 subtracted by the p-value of Z when X = 58.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{58.6 - 53}{2.8}

Z = 2

Z = 2 has a p-value of 0.9772

1 - 0.9772 = 0.0228

0.0228*100% = 2.28%

2.28% of faculty members work more than 58.6 hours a week.

6 0
3 years ago
The electric cooperative needs to know the mean household usage of electricity by its non-commercial customers in kWh per day. A
anygoal [31]

Answer:

The 90% confidence interval for the mean usage of electricity is between 17.4 kwH and 17.6 kwH

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

So

M = 1.645*\frac{2.4}{\sqrt{796}} = 0.14

The lower end of the interval is the mean subtracted by M. So 17.5 - 0.14 = 17.4 kwH

The upper end of the interval is M added to the mean. So 17.5 + 0.14 = 17.6 kwH

The 90% confidence interval for the mean usage of electricity is between 17.4 kwH and 17.6 kwH

4 0
3 years ago
Use the grouping method to factor the polynomial below.<br><br> x^3+4x^2-3x-12
Rina8888 [55]

Answer:

(x+4) (x^2-3)

Step-by-step explanation:

Hope this helps

6 0
3 years ago
Read 2 more answers
What type of counting problem is this? Tatiana has a special puzzle in which all of the pieces fit together in any way. There is
pshichka [43]

Answer:

It is permutation without repetition. I just took the quiz. This is a permutation because different orderings of the pieces produce different pictures. Repetition is not allowed because there are a limited number of puzzle pieces.

Step-by-step explanation:

5 0
3 years ago
T<br> Radius:<br> 4<br> inches<br> Diameter:<br> Circumference:
Travka [436]

Answer:

diameter 8

and i think the circumference is 25.12

Step-by-step explanation:

4+4=8

3.14(8)

7 0
3 years ago
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