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3 years ago

Ork.

Mathematics

2 answers:

coldgirl [10]3 years ago

7 0

There are nine girls at the park because 5 leave and there’s 3 left the 6 come which makes nine

velikii [3]3 years ago

5 0

Answer: 9 girls

Step-by-step explanation: 8 originally. 8-5 is 3. 6 more come. 3 + 6 Is 9. So 9. Also nice picture

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Will someone please answer (ALL) the questions that’s are highlighted? Except for 14 & 16..

Zolol [24]

Hello!

2.
To find the area of a kite we use the equation $\frac{pq}{2}$

p is the line in the kite that goes from top to bottom
q is the line in the kite that goes from left to right

put in the values

$\frac{10 * 11}{2}$

Multiply

$\frac{110}{2}$

Divide

55

The answer is 55
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4.

I believe the answer is 770 yds squared
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6.

The ratio is 12:7
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8.

I do not know how to do 8 sorry
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10.
I can't see the whole picture put I will do my best

Since the angle inside the circle is 50° the side is also 50°
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12.
I do not know how to do 12 sorry

Hope this helps!

7 0

4 years ago

Can someone please help me with this?

Anettt [7]

Answersorry

Step-by-step explanation:sorry idk

7 0

4 years ago

How many liters are there in 70 quarts? 1 qt ≈ 0.95 L

nasty-shy [4]

Answer:

66.5 liters

Step-by-step explanation:

0.95 x 70 is 66.5

5 0

3 years ago

(Hehe...Please ignore the markings)

inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0

3 years ago

What is the distance between the zeros of the function defined by 6(2x2+x-8)-2x(2x-1)

Evgen [1.6K]

12x^2+x-8 - (4x^2-1)
12x^2+x-8-4x^2+1
8x^2 + x - 7 =0

8x^2 + 8x - 7x -7 = 0
8x ( x + 1 ) - 7 ( x + 1 ) = 0
(8x - 7) (x + 1) =0
8x -7 = 0
x + 1 = 0
x = 7/8 and x = -1

7 0

3 years ago