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slavikrds [6]
3 years ago
5

A company sold 123 mobile phones for ₹ 8000 each. With the same money, 48 music systems were bought. Find the cost of one music

system.
Mathematics
1 answer:
vova2212 [387]3 years ago
6 0

Answer:

Step-by-step explanation:

123 X 8000 = 984000

984000/48 = 20500(PUT EURO SIGN)

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Subtract: 6a3 - 2a2 + 4 from 5a3 - 4a + 7
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Point D is the centroid of Triangle ABC. Find CD and CE.<br> DE = 9
sukhopar [10]

Given:

Point D is the centroid of Triangle ABC and DE = 9.

To find:

The measures of CD and CE.

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We know that, centroid is the intersection of medians and it divides each median in 2:1.

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Let the measures of CD and DE are 2x and x respectively.

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x=9

Now,

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6 0
3 years ago
How to prove this???
swat32
\cos^3 2A + 3 \cos 2A \\&#10;\Rightarrow \cos 2A (\cos^2 2A + 3) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3)  \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\&#10;\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ &#10;\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) &#10;

go to right side now

4( \cos^6 A - \sin^6 A)\\&#10;\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)

use x^3 - y^3 = (x-y)(x^2 + xy + y^2) and x^3 + y^3 = x^2 - xy + y^2

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\&#10;\Rightarrow  4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\&#10;~\quad  \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)

so \sin^2 A + \cos^2 A = 1

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\&#10; \Rightarrow Left hand side
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