Answer:
<em>Graph below</em>
Step-by-step explanation:
<u>Transformations</u>
Triangle ABC has coordinates A=(-4,2) B=(-2,6) C=(3,2)
We'll use the transformation (x,y) -> (2x, y+3) to map it to the triangle A'B'C'. Let's calculate the coordinates:
A'=(-8,5)
B'=(-4,9)
C'=(6,5)
The image below shows both triangles in the same grid
Answer:
The answer to part B is B.
Step-by-step explanation:
Could you take another photo so I can see the bottom of the page?
Answer:
x = 27°, ∠JLK = 55°
Step-by-step explanation:
From the diagram in the question above,
The exterior angle of a triangle is equal to the sum of the two opposite side
3x+13 = 39+(2x+1)
3x+13 = 40+2x
collect like terms and solve for x
3x-2x = 40-13
x = 27°.
∠JKL = 2x+1
Substitute the value of x
∠JKL = 2(27)+1
∠JKL = 54+1
∠JKL = 55°
The measurement should be 130 according to my calculations
Answer:
<em>tan 19° = 0.3443</em>
Step-by-step explanation:
<u>Value Of Trigonometric Functions</u>
The value of the tangent of 19° cannot be expressed in exact form, that it, as a function of radicals or known constants as pi.
We need to use a calculator, computer, or similar technology to find the required value. We use a scientific calculator to get:
tan 19° = 0.3443
To the nearest ten-thousandth
