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Neko [114]
3 years ago
11

Which element has 3 valence electrons in the 4dsublevel

Chemistry
1 answer:
Simora [160]3 years ago
6 0

Niobium is the element your looking for.

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How many non-bonding electrons does phosphorus have?
Eddi Din [679]
10 non-bonding electrons 
8 0
3 years ago
Read 2 more answers
2.Which term best describes the processes that change rocks and mountains on Earth’s surface over time?
ArbitrLikvidat [17]

Answer:

B. weathering

or erosion

4 0
2 years ago
Which compounds give a 1h nmr spectrum with two signals in a ratio of 2:3?
spayn [35]

Four option are provided as,

CH3CH2OCH2CH3

CH3CH2Cl

CH3CH2CH3

CH3OCH2CH2OCH3


CH3CH2Cl having 2 peaks of H NMR as 1st peak for quartet of 2 H and 2nd peak of triplet of 3 H and thus the ratio of both the peak is 2 :3 as the ratio indicates the number of hydrogen corresponds to each peak.


8 0
3 years ago
Calculate the amount of heat needed to melt of solid octane () and bring it to a temperature of . Round your answer to significa
elixir [45]

Answer:

85.0 kJ

Explanation:

Calculate the amount of heat needed to melt 160. g of solid octane (C8H18 ) and bring it to a temperature of 99.2 degrees c. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.

To melt 160 g of octane and bring it's temperature to 99.2°C

(from literature)

Heat of fusion of Octane = 20.740 kJ/mol

Melting point of octane = -57°C

Boiling point of Octane = 125.6 °C

Molar mass of octane = 114.23 g/mol

Heat capacity of octane = 255.68 J/K.mol

So, it is evident that Octane is still a liquid at 99.2°C.

So, the required heat is the heat required to melt octane and raise the temperature of Octane liquid to 99.2°C

First, we convert the mass of octane given to number of moles as the heat parameters provided by literature are given in molar units.

Number of moles = (mass)/(Molar mass)

Number of moles of octane = (160/114.23) = 1.401 moles

Heat required to melt the octane = nL = (1.401×20.740) = 29.05674 kJ

Heat required to raise the temperature of already melted octane from its melting temperature of -57°C to 99.2°C

= nCΔT

n = 1.401 moles

C = 255.68 J/K.mol

ΔT = (99.2 - (-57)) = 156.2°C (same as a temperature difference of 156.2 K)

Heat required to raise the temperature of already melted octane from -57°C to 99.2°C

= (1.401×255.68×156.2)

= 55,952.04 J = 55.952 kJ

Total heat required to melt the 160 g of Octane and raise its temperature to 99.2°C

= 29.05674 + 55.952 = 85.01 kJ = 85.0 kJ

Hope this Helps!!!

8 0
3 years ago
A sample of 1.00 moles of oxygen at 50°C and 98.6 kPa occupies a volume
Kryger [21]

Answer:

27.22dm³

Explanation:

Given parameters:

number of moles = 1 mole

temperature  = 50°C, in K gives 50+273 =323K

Pressure  = 98.6kpa in atm, gives 0.973atm

Unknown:

Volume of the gas = ?

Solution:

Since the unknown is the volume of gas, applying the ideal gas law will be appropriate in solving this problem.

The ideal gas law is mathematically expressed as;

            Pv = nRT

where P is the pressure of the gas

          V is the volume

          n is the number of moles

          R is the gas constant

         T is the temperature

Input the parameters and solve for V;

                    0.973 x V  = 1 x 0.082 x 323

                           V  = 27.22dm³

5 0
3 years ago
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