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2 years ago

A certain star is 2.4 x 102 light years from the Earth. One light year is about 5.9 x 1012 miles. How far

Mathematics

1 answer:

Studentka2010 [4]2 years ago

6 0

Answer:

2.5 x $10^{15}$ miles

Step-by-step explanation:

We are given that 1 light year ≈ 5.9 x $10^{12}$ miles so:

4.3 x 10² light year · 5.9 x $10^{12}$ miles
1 light year

Multiply 4.3 an 5.9 and round to 2 significant digits then add the exponents:

≈25 x $10^{14}$

This is not the scientific notation since the number is not between 0 and 10 so we move the decimal point by 1 place to the left. We then add 1 to the exponent to obtain the final answer:

≈ 2.5 x $10^{15}$ miles

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Jean and Jericho who are playing in the school grounds decided to sit on a

Natalija [7]

We want to see underline the correct part in each statement.

1) This situation illustrates (direct, inverse) variation.
2) The two quantities that must vary in this situation are (weight and 
distance from the center, height and weight).
3) The heavier the kid, the (closer, farther) he/she should be at the
center to balance the seesaw?
4) When Jean moves farther from the center, Jericho tends to go (up,
down).
5) If Jericho moves closer to the center, Jean tends to go (up, down).

So, Jean and Jericho are playing on a seesaw.

Jean is heavier than Jericho.

Now, notice that a seesaw is a lever. So it "amplificates" the force that you apply in one end to lift the weight that is on the other end. Depending on the form of the lever and the weights, the force that you need to do changes.

If we define:

W₁ = Jean's weight.
d₁ = Jean's distance to the center.
W₂ = Jericho's weight.
d₂ = Jericho's distance to the center.

We must have:

W₁*d₁ = W₂*d₂

Then:

1) This situation illustrates (direct, inverse) variation.

d₁, the position of Jean, varies inversely with respect to Jean's weight.

2) The two quantities that must vary in this situation are (weight and

distance from the center, height and weight).

(by the equation above)

3) The heavier the kid, the (closer, farther) he/she should be at the

center to balance the seesaw?

By the given equation, we see that d₁ must be smaller than d₂.

And the last two are trivial:

4) When Jean moves farther from the center, Jericho tends to go (up,

down).

5) If Jericho moves closer to the center, Jean tends to go (up, down).

If you want to learn more, you can read:

brainly.com/question/18320907

7 0

2 years ago

En la expresion algebraica x², ¿que indica el número 2 en la base x?

tino4ka555 [31]

Answer:

En la expresión, 2 representa la cantidad de veces que multiplicas x por sí mismo.

**Lo siento si mi español es malo, el inglés es mi primer idioma.

Step-by-step explanation:

$8^{2}$ = 8 × 8 = 64

$y^2$ = y × y

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3 years ago

What is the solution to the system of equations graphed below? y=-4x + 33 y=5/3x-1

Black_prince [1.1K]

Answer:

x = 6

y = 9

This is the correct answer. Not satisfied? Check out this answer expert verified answer of the same question but with a step-by-step explanation. This answer is just a simple version of rocioo's correct answer.

Expert Verified Answer (of this same question but with a step-by-step explanation):

This is the link to rocioo's answer. brainly.com/question/13675950

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3 years ago

Read 2 more answers

Anais bought 212212 yards of ribbon. She had 2 feet 8 inches of ribbon left after trimming some curtains. How many inches of rib

jonny [76]

2 1/2 yds = 2.5 x 36 = 90 inches...what she started with

2 ft 8 in = 2(12) + 8 = 32 inches...what she had left

90 - x = 32
90 - 32 = x
x = 58 inches....so she used 58 inches

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3 years ago

Lelia says that 75% of a number will always be greater than 50% of a number. Complete the inequality to support Lelia's claim an

worty [1.4K]

Answer:

Let 'x' and 'y' be two different numbers.

Leila says that 75% of a number will always be greater than 50% of a number. The inequality that represents this statement is the following:

0.75x > 0.5y

Let x = 100 and y=200. We have that:

0.75(100) > 0.5(200)

75 > 100 ❌ INCORRECT ❌

Given that we found a case in which 75% of a number is not greater than 50% of a number, we can conclude that Leila's claim is incorrect.

3 0

3 years ago