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3 years ago

11

The Temperature started out at 92C in the morning and went down to -13C at noon. It stayed at that temparature for six hours and

then rose 7C. How far below the freezing point ( 0c ) was the temperature at 6 p.m?

1 answer:

ioda3 years ago

7 0

the tempayure was at six because it was at 92c and went down to -13c then rose 7c so that means it was at 6 by 6 a.m.

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Following are the solution to this question:

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$Principle= \$ 600\\Rate = \ 8 \%\\Time= \ 5$

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$\to \frac{P \times R \times T}{100} \\\\\to \frac{(600 \times 8 \times 5)}{100}\\\\ \to 240$

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$= 600 + 240 \\\\= 840$

In question (2):

$Principle= \$ 12,450\\Rate = \ 7.25 \%\\Time= \ 6$

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$\to \frac{P \times R \times T}{100} \\\\\to \frac{(12,450 \times 7.25 \times 6)}{100}\\\\ \to 5,415.75$

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