Answer:
Explanation:
Radius = 9.5 x 10⁻² m
area of circle = 3.14 x (9.5 x 10⁻² )²
A = 283.38 x 10⁻⁴ m²
magnetic moment = area x current
M = 283.38 x 10⁻⁴ x 5
= 1416.9 x 10⁻⁴ Am²
Torque = MBsinθ
M is magnetic moment , B is magnetic field .
Max torque = 1416.9 x 10⁻⁴ x 3.4 x 10⁻³ , for θ = 90
= 4817.46 x 10⁻⁷
= 481.7 x 10⁻⁶
= 481.7 μ J
Energy = - MBcosθ
Max energy when θ = 180
MB = 4817.46 x 10⁻⁷ J
Min energy = - 4817.46 x 10⁻⁷ for θ = 0
That would be the independent variable.
Dependent variable changes according to the independent variable
I honestly don’t know about graphing and stable variables never heard of it before
Answer:
a) 15.77 m/sec2
b) 13.3 deg
Explanation:
we are given;
Flea force = F1=1.07×10⁻5 N j
Breeze force = F2 = 1.14× 10⁻6 N (-j
mass of flea =6.0 ×10⁻7 kg
So net force on the flea=F1+F2+weight of flea=1.07×10⁻5 j +1.14× 10⁻6 i + 6.0 ×10⁻7 (-j) ×9.8= ma
==> ma = 1.07×10⁻5 j - 0.588×10⁻5 j + 0.114×10⁻5 i
==> ma= 0.482 ×10⁻5 j +0.114×10⁻5 i
==> ma = 0.114×10⁻5 i +0.482 ×10⁻5 j
== a = (0.114×10⁻5 i +0.482 ×10⁻5 j) / 6.0 ×10⁻7
==> a =
==>a= (1.9 j+8.03 i ) m/sec2
mag of a
= 15.77 m/sec2
direction angle = tan⁻1(1.9/8.03)=13.3°
The dispersed particles of a colloid exhibit brownian motion, in which they move _____. ... The dispersed particles of a colloid exhibit brownian motion, in which they move in a chaotic manner without a discernible pattern.
Answer:
Diagrams containing answers are attached
Explanation:
Diagram needed to solve the question was missing, So I have attached it with this answer. Also the diagonals of a parallelogram can only be equal to A + B (Not AB as given in your statement).
~~~~~~~~~~~~~~~~~~~~~~~ ANSWER FROM HERE ~~~~~~~~~~~~~~~~~~~~~~
First of all let us understand the law of parallelogram for vector addition. It states that, <em>"If two vectors are along the adjacent sides of a parallelogram, then their resultant is given by the vector that is a diagonal passing through the point of contact of these vectors".</em>
I have attached the diagrams describing the vectors A and B for the cases.
From diagram, it is clear that the magnitude of A and B is equal (balancing horizontal forces) and the resultant A + B is equal to the weight of the stone W (balancing vertical forces). Therefore, we can mathematically write:
A = B - - - - - (i)
& A + B = W - - - - - - (ii)
Putting A = B in equation (ii), we get
B + B = W
2B = W
<u>B = W/2</u>
Putting B = W/2 in equation (i), we get
<u>A = W/2</u>
Hence, magnitudes of both A and B are approximately W/2