Answer:
0.3619sec
Explanation:
Given that
Mass,m=148 g
Length,L=13 cm
Velocity,u'(0)=10 cm/s
We have to find the position u of the mass at any time t
We know that
Where
u(0)=0
Substitute the value
Substitute u'(0)=10
Substitute the values
Period =T = 2π/8.68
After half period
π/8.68 it returns to equilibruim
π/8.68 = 0.3619sec
1. <span>FX = 0 since the bottom charges are symmetrical about the y axis and the top charge is aligned with the y-axis
3. </span><span>FY > 0 since the bottom charges do not equate the top charge. The bottom charges have horizontal components which is less than q and adding them all, will not result to 3q.</span>
The time it takes the plane to change its velocity is 9s.
<h3>What is time?</h3>
Time can be defined the measured or measurable period during which an action, process, or condition exists or continues.
To calculate the time it takes the airplane to change its velocity, we use the formula below.
Formula:
- t = (v-u)/a.......... Equation 1
Where:
- a = Acceleration
- v = Final velocity
- u = Initial velocity
- t = time
From the question,
- v = 40 m/s
- u = 22 m/s
- a = 2 m/s²
Substitute these values into equation 1
- t = (40-22)/2
- t = 18/2
- t = 9s
Hence, the time it takes the plane to change its velocity is 9s.
Learn more about time here: brainly.com/question/2854969
Answer:
b) true. The jobs are equal
Explanation:
The work on a body is the scalar product of the force applied by the distance traveled.
W = F. d
Work is a scalar, the work equation can be developed
W = F d cos θ
Where θ is the angle between force and displacement
Let's apply these conditions to the exercise
a) False, if we see the expression d cosT is the projection of the displacement in the direction of the force, so there may be several displacement, but its projection is always the same
b) true. The jobs are equal dx = d cosθ
c) False, because the force is equal and the projection of displacement is the same
d) False, knowledge of T is not necessary because the projection of displacement is always the same
e) False mass is not in the definition of work