Question

When an object threw to the free space to make an angle of 25 degree at an initial speed of 15 m/sec, the ball takes time to reach another position 1.12 sec. Find the travelling path of the object.

Answer 1

Answer:

The horizontal distance traveled by the projectile is 15.23 m.

Explanation:

Given;

angle of projection, θ = 25⁰

initial velocity of the projectile, u = 15 m/s

time of flight, t = 1.12 s

The the travelling path of the object is calculated as the range of the projectile

$R = u_x t\\\\R = (15\ Cos \ 25^0) \times 1.12\\\\R = 13.595 \times 1.12\\\\R = 15.23 \ m$

Therefore, the horizontal distance traveled by the projectile is 15.23 m.