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max2010maxim [7]
4 years ago
9

A negatively charged rod is placed near two neutral metal spheres, as shown below. Which statements describe the charging method

shown? Check all that apply.
Physics
2 answers:
vova2212 [387]4 years ago
6 0
<span><em>I just took the test and the following are the correct answer:</em>

</span>✔ The spheres develop opposite charges.✔ Electrons move from Sphere A to Sphere B.<span>✔</span> The spheres are charged through induction.

<em>Hope This Helps.</em>
grin007 [14]4 years ago
3 0
<h3>Answer;</h3>
  • <em>The spheres develop opposite charges. </em>
  • <em>Electrons move from Sphere A to Sphere B. </em>
  • <em>The spheres are charged through induction.</em>
<h3><u>Explanation;</u></h3>
  • <u><em>When a negatively charged rod is placed near two neutral metal spheres, the spheres will develop opposite charges, because the neutral metal spheres have both negative and positive charges. </em></u>From the basic law of electrostatics unlike charges attracts and like charges repel.
  • Thus, <em><u>the sphere will develop opposite charges, electrons will move from Sphere A to sphere B,</u></em> hence we say that the spheres will be charged by induction such that sphere A will acquire a positive charge while sphere B will acquire negative charge.
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Explanation:

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An electric current of 200 A is passed through a stainless steel wire having a radius R of 0.001268 m. The wire is L = 0.91 m lo
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Answer:

The value is   T_m  =  435.2 \  K

Explanation:

From the question we are told that  

   The  current is  I  =  200 \ A

   The radius is  R =  0.001268 \  m

   The  length of the wire is  L  =  0.91 \  m\

    The  resistance is  R  =  0.126 \  \Omega

    The  outer surface temperature is  T _o  =  422.1 \  K

    The average thermal conductivity is  \sigma  =  22.5 W/mK

   

Generally the heat generated in the stainless steel wire is mathematically represented as  

    Q =  \frac{Power}{ \pi r^2L}

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       T_m  =  422.1  +  \frac{1.096*10^{-9} * 0.001268^2}{6 * 22.5}

       T_m  =  435.2 \  K

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