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AysviL [449]
3 years ago
6

With a population standard deviation of 10 and a sample size of 4, what is the standard error of the mean

Mathematics
1 answer:
NikAS [45]3 years ago
7 0

With a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the meanWith a population standard deviation of 10 and a sample size of 4, what is the standard error of the mean

Step-by-step explanation:

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Answer:

y = 1x - 4

Step-by-step explanation:

y = mx + b

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A market researcher for Eric’s Electronics wants to study TV viewing habits of residents in Chicago. The individuals in the surv
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Answer:

Step-by-step explanation:

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Since the sample size is large and the population standard deviation is known, we would use the following formula and determine the z score from the normal distribution table.

Margin of error = z × σ/√n

Where

σ = population standard Deviation

n = number of samples

From the information given

1) x = 17.5

σ = 5

n = 50

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.9 = 0.1

α/2 = 0.1/2 = 0.05

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.05 = 0.95

The z score corresponding to the area on the z table is 1.645. Thus, confidence level of 90% is 1.645

Margin of error = 1.645 × 5/√50 = 1.16

Confidence interval = 17.5 ± 1.16

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Step-by-step explanation:

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