Moles = n = 3.91 mol
Pressure = P = 5.35 atm
Temperature = T = 323 K
Volume = V = ?
Formula used: Ideal Gas Equation is used,
P V = n R T
Solving for V,
V = n R T / P
Putting Values,
V = (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm
V = 19.36 L
26.25g
Explanation:
Given parameters:
Percentage of NaCl in ocean water = 3.5%
Mass of given seawater = 750g
Unknown:
Mass of NaCl in the seawater = ?
Solution:
This is a simple percentage problem:
We have been given that ocean water contains 3.5% of NaCl;
Therefore;
Mass of NaCl in seawater = Percentage of NaCl in ocean water x Mass of seawater
Mass of NaCl in seawater =
x 750g = 26.25g
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<span>D). Planet, Solar System, Galaxy, Universe</span>
V₁ = 420 mL
T₁ = 210 K
V₂ = ?
T₂ = 250 K
(Answer is 500 mL)
It is because aluminum cannot be recycled once corroded or used in reactions