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serg [7]
3 years ago
9

Given the reaction: 4Na + O2 → 2Na2O How many moles of oxygen are completely consumed in the production of 1.00 mole of Na2O?

Chemistry
2 answers:
Lorico [155]3 years ago
8 0

Answer : 0.5 moles of oxygen are completely consumed in the production of 1.00 mole of Na_2O

Solution : Given,

Moles of Na_2O = 1 mole

The given balanced reaction is,

4Na+O_2\rightarrow 2Na_2O

From this balanced reaction, we conclude that

As, 2 moles of Na_2O produces from 1 moles of O_2

So, 1 mole of Na_2O produces from \frac{1}{2}=0.5 moles of O_2

Therefore, 0.5 moles of oxygen are completely consumed in the production of 1.00 mole of Na_2O

Levart [38]3 years ago
4 0
The answer is 0.5 moles because if 1 moles of o2 is consumed to produce 2 moles of Na2O, then 0.5 moles of o2 will be consumed to produce 1 mole of Na2O.<span />
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216 J of energy is required to raise the temperature of a piece of aluminum from 15.0º C to to 35º C.
ddd [48]

Answer: 12g

Explanation:

The amount of energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 216 joules

Mass of aluminium = ? (let unknown value be Z)

C = 0.90 JºC-1g-1

Φ = (Final temperature - Initial temperature)

= 35°C - 15°C = 20°C

Then, Q = MCΦ

216 J = Z x 0.90 JºC-1g-1 x 20°C

216 J = Z x 18 J°g-1

Z = (216J/18 J°g-1)

Z = 12g

Thus, the mass of the aluminium is 12grams

8 0
4 years ago
Can I please Get Help with this question ‍♂️ ?
Nitella [24]

Answer:

Mg(NO4)2 is 180.3 g/mol

Explanation:

First find the substance formula.

Magnesium Nitrate.

Magnesium is a +2 charge.

Nitrate is a -1 charge.

So to balance the chemical formula,

We need 1 magnesium atom for every nitrate atom.

2(1) + 1(-2) = 0

So the substance formula is Mg(NO4)2.

Now find the molar mass of Mg(NO4)2.

Mg = 24.3 amu

N = 14.0 amu

O = 16.0 amu

They are three nitrogen and twelve oxygen atoms.

So you do this: 24.3 + 14.0(2) + 16.0(8) = 180.3 g/mol

So the molar is mass is 180.3 g/mol.

The final answer is Mg(NO4)2 is 180.3 g/mol

Hope it helped!

7 0
3 years ago
State Boyle's, Charles's, and Gay-Lussac's laws using sentences, then equations
dimaraw [331]

Explanation:

1. Boyle's Law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}      (At constant temperature and number of moles)

P_1\times {V_1}=P_2\times V_2

2. Charles' Law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T    (At constant pressure and number of moles

\frac{V_1}{T_1}=\frac{V_2}{T_2}

3. Gay Lussac's Law states that tempertaure is directly proportional to the pressure of the gas at constant volume and number of moles of gas

P\propto T    (At constant volume and number of moles)

\frac{V_1}{n_1}=\frac{V_2}{n_2}

7 0
3 years ago
Which of the following is the name of the process scientists use to gain
kobusy [5.1K]

Scientific method

Explanation:

The scientific method is the name of the process scientists use to gain knowledge about the physical world.

The scientific method is a systematic approach into the study of nature. It follows the following processes:

  • Detailed observation
  • Asking of question
  • Formulation of hypothesis
  • Experimentation
  • Analysis and interpretation
  • Conclusion

learn more:

Experiment brainly.com/question/1621519

#learnwithBrainly

8 0
3 years ago
The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) +
Mnenie [13.5K]

Answer: (a) The solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b) The solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

Explanation:

(a)  Chemical equation for the given reaction in pure water is as follows.

           CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)

Initial:                         0            0

Change:                    +x           +x

Equilibm:                   x             x

K_{sp} = 1.2 \times 10^{-6}

And, equilibrium expression is as follows.

          K_{sp} = [Cu^{+}][Cl^{-}]

       1.2 \times 10^{-6} = x \times x

             x = 1.1 \times 10^{-3} M

Hence, the solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b)  When NaCl is 0.1 M,

       CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq),  K_{sp} = 1.2 \times 10^{-6}

   Cu^{+}(aq) + 2Cl^{-}(aq) \rightleftharpoons CuCl_{2}(aq),  K = 8.7 \times 10^{4}

Net equation: CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

               K' = K_{sp} \times K

                          = 0.1044

So for, CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

Initial:                     0.1                 0

Change:                -x                   +x

Equilibm:            0.1 - x                x

Now, the equilibrium expression is as follows.

              K' = \frac{CuCl_{2}}{Cl^{-}}

         0.1044 = \frac{x}{0.1 - x}

              x = 9.5 \times 10^{-3} M

Therefore, the solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

7 0
3 years ago
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