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3 years ago

Which type of motor is shown below?

Physics

1 answer:

Minchanka [31]3 years ago

8 0

It would be a magnetic motor, see how its hovering in the middle? its from magnetic forces

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If the rifle is stopped by the hunter's shoulder in a distance of 3.23 cm, what is the magnitude of the average force exerted on

never [62]

By conservation of momentum, the initial recoil speed of the rifle is:
u = 904kg * 0.0106 kg / 3.53 kg = 2.7146 m/s

The final recoil speed v is zero in a distance of d = 0.0346 m

So the rifle's acceleration is a = (0 - u^2) / 2*d = -2.7146^2 / 2*.0323 m/s^2
a = -114.07m/s^2

6 0

3 years ago

An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through a potential difference that

zzz [600]

Answer with Explanation:

We are given that

Charge on alpha particle=q=2 e= $2\times 1.6\times 10^{-19} C$

1 e= $1.6\times 10^{-19} C$

Mass of alpha particle=m= $6.64\times 10^{-27} kg$

Potential difference,V= $1.97\times 10^6 V$

Magnetic field,B=3.49 T

a.Speed of alpha particle=v= $\sqrt{\frac{2 qV}{m}}$

By using the formula

$v=\sqrt{\frac{2\times 2\times 1.6\times 10^{-19}\times 1.97\times 10^6}{6.64\times 10^{-27}}$

$v=1.38\times 10^7 m/s$

b.Magnetic force,F $=qvB=2\times 1.6\times 10^{-19}\times 1.38\times 10^7\times 3.49=1.5\times 10^{-11} N$

F= $1.5\times 10^{-11} N$

c.Radius of circular path, r= $\frac{mv^2}{F}$

$r= \frac{6.64\times 10^{-27}\times (1.38\times 10^7)^2}{1.5\times 10^{-11}}$

r=0.084 m

5 0

3 years ago

Consider a 24.0 V storage battery that can transfer, over the course of its useful lifetime, a total charge equivalent to 340000

xeze [42]

Answer:

Explanation:

Given that,

Potential difference of battery is

V = 24V

Total charge battery can transferred

q = 340,000C

Work done by the battery?

Work done is given as

W = qV

Where q is charge in Columbs

V is potential difference in Volts

Then, W = qV

W = 340,000×24

W = 8,160,000 J

Work done by the battery over it's useful life time is 8,160,000J

5 0

3 years ago

A 100-watt lightbulb radiates energy at a rate of 100 J/s. (The watt, a unit of power, or energy over time, is defined as 1 J/s.

fomenos

Answer:

$N=2.18\cdot 10^{20}photons/s$

Explanation:

The energy of a photon is: $E=h\nu=h\frac{c}{\lambda}$ when h is the Planck constant.

$h=6.63\cdot 10^{-34}Js$

$c=3.8\cdot 10^{8}m/s$

Then, we calculate the energy of a photon with a wavelength equal to 550 nm.

$E= 4.58\cdot 10^{-19}J$

To find the number of photons we can use this equation:

$N=\frac{P}{E}=\frac{100}{4.58\cdot 10^{-19}}=2.18\cdot 10^{20} photons/s$

Have a nice day!

7 0

3 years ago

Which of the following is NOT true of all the inner planets?

Artist 52 [7]

Hi there! :)

$\large\boxed{\text{B. They are called gas giants.}}$

In the solar system, we can categorize the planets as such:

Inner planets: Mercury, Venus, Earth, Mars

Outer planets: Jupiter, Saturn, Uranus, Neptune

The Inner planets are the only planets that consist of solid rock. They also do not have rings and have impact craters due to their early formation.

In comparison, all of the outer planets are primarily made up of gaseous material and contain rings.

Therefore, the correct choice is B.

7 0

3 years ago