Question

The inductance of a closely packed coil of 560 turns is 8.9 mH. Calculate the magnetic flux through the coil when the current is 7.0 mA.

Answer 1

Answer:

The magnetic flux through the coil is $1.1125\times10^{-7}\ Wb$

Explanation:

Given that,

Number of turns = 560

Inductance = 8.9 mH

Current = 7.0 mA

We need to calculate the magnetic flux

Using formula for magnetic flux

$L=\dfrac{N\phi}{I}$

$\phi=\dfrac{LI}{N}$

Where, L = inductance

I = current

N = number of turns

Put the value into formula

$\phi=\dfrac{8.9\times10^{-3}\times7.0\times10^{-3}}{560}$

$\phi=1.1125\times10^{-7}\ Wb$

Hence, The magnetic flux through the coil is $1.1125\times10^{-7}\ Wb$

Answer 2

Answer:

$0.11\times 10^{-6}weber$

Explanation:

We have given number of turns N = 560

Inductance L = 8.9 mH

Current through the coil = 7 mA

Inductance of the coil is given as $L=\frac{N\Phi }{I}$

Where N  is number of turns I is current and $\Phi$ is flux

So $\Phi =\frac{LI}{N}=\frac{8.9\times 10^{-3}\times 7\times 10^{-3}}{560}=0.11\times 10^{-6}weber$