Look at Figure X diagrammed on the graph below. Which of the following statements are true
1 answer:
Check the picture below.
so, if we slap the bottom surplus to the empty area on the top, we can pretty much close off those squares above, that gives a solid area of at least a 4x5 square, the red part and the yellow part there, and that'd give us a perimeter of 4+4+5+5 = 20 at least.
we might also be able to augment the left-right sides together to close off those squares as well, but even if we did, our area will just be about a 4x6 or 24 square units.
A) is the area larger than 14 square units? ✔
B) is the area less than 35 square units? ✔
C) is the perimeter more than 16? ✔
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Part 1:
Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.
Thus, half the angle formed by the chord at the centre of the circle is given by:
Now,
Therefore, the radius of the circle is 10.4 cm to 1 d.p.
Part 2I:
Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then
Now,
Part 2II:
Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:
Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.
Thus, half the angle formed by the chord at the centre of the circle is given by:
Now,
Therefore, the radius of the circle is 10.4 cm to 1 d.p.
Part 2I:
Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then
Now,
Part 2II:
Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:
Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.