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wel
3 years ago
14

Given that

rac{4x-y}{3y} = \frac{1}{2}" alt="\frac{4x-y}{3y} = \frac{1}{2}" align="absmiddle" class="latex-formula"> , find the value of \frac{x}{y}
Mathematics
1 answer:
Aleks [24]3 years ago
7 0

Answer:

\frac{x}{y} = \frac{5}{8}

Step-by-step explanation:

Given

\frac{4x-y}{3y} = \frac{1}{2} ( cross- multiply )

2(4x - y) = 3y ← distribute left side

8x - 2y = 3y ( add 2y to both sides )

8x = 5y ( divide both sides by 8 )

x = \frac{5}{8} y ( divide both sides by y )

\frac{x}{y} = \frac{5}{8}

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When a polynomial f(x) is divided by 2x-3,the quotient is x^2-x+2 and the remainder is -1. Find the f(x)​
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Answer:

f(x) = 2x³ - 5x² + 7x - 7

Step-by-step explanation:

In the division statement: m ÷ n = q + \frac{r}{n}

  • m is the dividend
  • n is the divisor
  • q is the quotient
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Let us use the fact above to solve the question

∵ f(x) is divided by (2x - 3), the quotient is x² - x + 2 and the remainder is -1

∴ f(x) is the dividend ⇒ m

∴ (2x - 3) is the divisor ⇒ n

∴ (x² - x + 2) is the quotient ⇒ q

∴ -1 is the remainder ⇒ r

→ Use the rule above to find f(x)

∵ f(x) = (x² - x + 2) × (2x - 3) + -1

∴ f(x) = (x² - x + 2)(2x - 3) - 1

→ Multiply the 2 brackets at first

∵ (x² - x + 2)(2x - 3) = x²(2x) + x²(-3) + -x(2x) + -x(-3) + 2(2x) + 2(-3)

∴ (x² - x + 2)(2x - 3) = 2x³ - 3x² - 2x² + 3x + 4x - 6

→ Add the like terms

∴ (x² - x + 2)(2x - 3) = 2x³ + (-3x² - 2x²) + (3x + 4x) - 6

∴ (x² - x + 2)(2x - 3) = 2x³ + (-5x²) + 7x - 6

∴ (x² - x + 2)(2x - 3) = 2x³ - 5x² + 7x - 6

→ Substitute it in f(x)

∴ f(x) = 2x³ - 5x² + 7x - 6 - 1

→ Add the like term

∵ f(x) = 2x³ - 5x² + 7x + (- 6 - 1)

∴ f(x) = 2x³ - 5x² + 7x + (-7)

∴ f(x) = 2x³ - 5x² + 7x - 7

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