The attraction that occurs between two oppositely charged atoms is called

In the equation y =cnat2 you wish to determine theinteger value (1,2 etc.) of the exponent n. the dimensions ofy, a, and t are k

kvasek [131]

NO. Since "c" has no dimensions, the value of its exponent "n" is irrelevant to dimensional analysis, and thus dimension analysis cannot be used to determine the value of "n".

Dimensional analysis is not applicable to proportionality constants, trigonometrical or exponential equations, equation consisting of sum or difference of some quantities and equation consisting of more than three fundamental quantities.

What is Dimensional analysis?

Dimensional Analysis is a problem-solving technique that makes use of the fact that any number or expression can be multiplied by one without changing its value.
It is also known as the Factor-Label Method or the Unit Factor Method. It is a practical method.

What is a dimensional analysis used for?

Dimensional analysis is a method used in engineering and the physical sciences to reduce physical properties like acceleration, viscosity, and energy to their three basic dimensions of length, mass, and time (T).

Learn more about Dimensional analysis

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5 0

2 years ago

3. What conclusion can you make about the electric field strength between two parallel plates? Explain your answer referencing P

KIM [24]

Answer:

From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

$E=\frac{F}{Q}$

But the force F

$F= \frac{kQ1Q2}{r^2}$

But the electric field intensity due to a point charge Q at a distance r meters away is given by

$E= \frac{\frac{kQ1Q2}{r^2}}{Q} \\\\\E= \frac{Q1}{4\pi er^2 }$

From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases

6 0

3 years ago

What is the electrical charge of a neutral atom that has lost on electron?

dybincka [34]

I believe it is positive.

6 0

4 years ago

As water heats in a pot on a stove, it might produce some mist above its surface right before the water begins to roll. What is

mr_godi [17]

When a liquid is heated, the molecules gain kinetic energy. As the liquid begins to boil they have enough energy to break the intermolecular attractions between their neighbors. This happens first at the surface before the volume below has enough energy to boil. Thus you see high energy water molecules escaping from the surface as mist.

4 0

4 years ago

Read 2 more answers

A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at In a few mi

Nataliya [291]

Answer:

2274 J/kg ∙ K

Explanation:

The complete statement of the question is :

A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at 15 °C. In a few minutes, she measures the final temperature of the system to be 40.0°C. What is the specific heat of the 400.0-g piece of metal, assuming that no significant heat is exchanged with the surroundings? The specific heat of this aluminum is 900.0 J/kg ∙ K and that of water is 4186 J/kg ∙ K.

$m_{m}$ = mass of metal = 400 g

$c_{m}$ = specific heat of metal = ?

$T_{mi}$ = initial temperature of metal = 100 °C

$m_{a}$ = mass of aluminum cup = 100 g

$c_{a}$ = specific heat of aluminum cup = 900.0 J/kg ∙ K

$T_{ai}$ = initial temperature of aluminum cup = 15 °C

$m_{w}$ = mass of water = 500 g

$c_{w}$ = specific heat of water = 4186 J/kg ∙ K

$T_{wi}$ = initial temperature of water = 15 °C

$T$ = Final equilibrium temperature = 40 °C

Using conservation of energy

heat lost by metal = heat gained by aluminum cup + heat gained by water

$m_{m} c_{m} (T_{mi} - T) = m_{a} c_{a} (T - T_{ai}) + m_{w} c_{w} (T - T_{wi} ) \\(400) (100 - 40) c_{m} = (100) (900) (40- 15) + (500) (4186) (40 - 15)\\ c_{m} = 2274 Jkg^{-1}K^{-1}$

7 0

4 years ago