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lana66690 [7]
3 years ago
15

An SUV is accelerated from rest to a speed v in a time interval t. Neglecting air resistance effects and assuming the engine is

operating at its maximum power rating when accelerating, determine the time interval for the SUV to accelerate from rest to a speed 2v.
a. 2t
b. 4t
c. 2.5t
d. 3t
Physics
1 answer:
kakasveta [241]3 years ago
4 0

Answer:

A. 2\cdot t

Explanation:

The SUV accelerates uniformly. In this case, speed (v) is directly proportional to time (t). That is:

v \propto  t (1)

v = k\cdot t

Where k is the proportionality constant.

Then, we eliminate this constant by creating the following relationship:

\frac{v_{1}}{t_{1}} = \frac{v_{2}}{t_{2}} (2)

If we know that v_{1} = v, t_{1} = t and v_{2} = 2\cdot v, then the time interval for the SUV to accelerate from rest to a speed 2\cdot v is:

\frac{v}{t} = \frac{2\cdot v}{t_{2} }

t_{2} = 2\cdot t

Hence, correct answer is A.

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5 0
3 years ago
If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?
vovikov84 [41]

Complete Question

In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is 130 m above the water. If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?

Answer:

The speed of the helicopter is u  =  7.73 \  m/s

Explanation:

From the question we are told that

   The height at which he let go of the brief case is  h =  130 m  

    The  time taken before the the brief case hits the water is  t =  6 s

Generally the initial speed of the  briefcase (Which also the speed of the helicopter )before the man let go of it is  mathematically evaluated using kinematic equation as

      s = h+  u t +  0.5 gt^2

Here s  is the distance covered by the bag at sea level which is zero

      0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>    0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>   u  =  \frac{-130 +  (0.5 * 9.8 *  6^2) }{6}

=>   u  =  7.73 \  m/s

     

7 0
3 years ago
Equation of motion, for a simplicity assume that the cart begins to moves at t=0 and reaches a speed of 0.44m/s at t=1.8 sec. Wr
nignag [31]

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6 0
3 years ago
ou are pushing a 20-kg box along a horizontal floor. Friction acts on the box. When you apply a horizontal force of magnitude 48
ziro4ka [17]

Answer:

The magnitude of the frictional force is 48.02 N

Explanation:

Mass of box = 20 kg

Weight of the box (Normal reaction) = mass × acceleration due to gravity = 20 ×9.8 = 196 N

Horizontal force applied = 48 N

Coefficient of friction = horizontal force ÷ normal reaction = 48 ÷ 196 = 0.245

Frictional force = coefficient of friction × normal reaction = 0.245 × 196 N = 48.02 N

5 0
3 years ago
Read 2 more answers
A wave traveling in water has a frequency of 250 Hz and a wavelength of 6.0 N. What is the speed of the wave?
enyata [817]
The speed of a wave is determined by the product of the frequency and the wavelength; we already have the wavelength and the frequency, so all we need to do is multiply them by each other and use our proper unit of measure.

Velocity (speed) = Frequency x Wavelength
V = 250 x 6
V = 1500

Your answer is 1500 m/s.

I hope this helps!
5 0
3 years ago
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