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inn [45]
3 years ago
15

State Newton's first law of motion .​

Physics
1 answer:
malfutka [58]3 years ago
4 0

Answer:

dis mans newton says if a body is at rest or moving at a constant speed in a straight linne it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force

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Kinetic Energy - What does it depend on?
Greeley [361]

Answer:

faster; more kinetic energy

Explanation:

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2 years ago
What kind of potential energy allows you to throw a ball
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Force.................
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3 years ago
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Chapter 36, Problem 007 Light of wavelength 586 nm is incident on a narrow slit. The angle between the first diffraction minimum
svp [43]

Answer:

d =4.77\times 10^{-5}\ m

Explanation:

given

wavelength of light  λ = 479 nm

                                   = 479 x 10⁻⁹ m

the angle

θ = 1.15 / 2 = 0.575°                

using                                              

condition for diffraction minimum ,

         d sinθ = m λ                        

for first minimum m = 1

       d sinθ = λ                      

therefore ,

slit width                                  

d =\dfrac{\lambda}{sin\theta}          

d =\dfrac{479\times 10^{-9}}{sin 0.575^0}

d =\dfrac{479\times 10^{-9}}{0.01}              

d =4.77\times 10^{-5}\ m                                                    

hence, the width of the slit is equal to d =4.77\times 10^{-5}\ m

3 0
3 years ago
A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at
baherus [9]

Hello!

Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.

\Sigma \tau = 0

We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)

- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)

Both of these act in opposite directions. Let's use the equation for torque:
\tau = r \times F

Doing the summation using their respective lever arms:

0 = L Tsin\theta  - dF_g

dF_g = LTsin\theta

Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:

tan\theta = \frac{H}{L}\\\\tan^{-1}(\frac{H}{L}) = \theta\\\\tan^{-1}(\frac{1.70}{2.200}) = 37.69^o

Now, let's solve for 'T'.

T = \frac{dMg}{Lsin\theta}

Plugging in the values:
T = \frac{(0.700)(4.00)(9.8)}{(2.200)sin(37.69)} = \boxed{20.399 N}

3 0
1 year ago
Its like almost 12 pm rn and i have school tomorrow so i dunno why im still up but i just wanna know how big the world is. like
tatiyna
The earth all the way around is 196.9 million miles
7 0
3 years ago
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