Answer:
A complete circuit is a complete loop with electricity flowing the way it's supposed to flow: from the battery, to the component, and back to the battery again. An open circuit is an incomplete loop, where the loop is broken at a particular point and electricity can't flow at all
Explanation:
So, you can show one with how the electricity flows right through and then how the loop is broken so the electricity wont really flow.
The equation v²=u²+2as will help with solving this equation
v is what we are trying to find
u=0
a=4.9
s=200
v²=0²+2*4.9*200
v=√(2*4.9*200)
v=√1960
v=44.3 m/s (3 sf)
Answer:
(a) 498.4 Hz
(b) 442 Hz
Solution:
As per the question:
Length of the wire, L = 1.80 m
Weight of the bar, W = 531 N
The position of the copper wire from the left to the right hand end, x = 0.40 m
Length of each wire, l = 0.600 m
Radius of the circular cross-section, R = 0.250 mm = 
Now,
Applying the equilibrium condition at the left end for torque:



The weight of the wire balances the tension in both the wires collectively:



Now,
The fundamental frequency is given by:

where

(a) For the fundamental frequency of Aluminium:


where


(b) For the fundamental frequency of Copper:


where


Answer:
b
Explanation:
see how far the bullet goes