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3 years ago

Viet Cong was the military force for

Mathematics

1 answer:

Aleks04 [339]3 years ago

7 0

Answer:

d.i think d is the correct answer

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A system of equations has zero solitions. Describe how the graph will look. Pls help

gavmur [86]

it will be a straight line

6 0

4 years ago

A veterinarian is visited by many pets and their owners each day. Before the doctor attends to each pet, an assistant records in

stepan [7]

Answer:

pets bcos a vetenarian is a doctor for animals and tha question also says their owners.

5 0

3 years ago

Find the perimeter and the area of the composite figure

ankoles [38]

Answer:

Part A) The approximate perimeter of the concrete region is $P=64.66\ yd$

Par B) The exact area of the concrete region is $A=(8\pi+162.4)\ yd^{2}$

Step-by-step explanation:

Part A) What is the approximate perimeter of the concrete region?

we know that

The perimeter of the composite figure is equal to

$P=\pi r+2(15.2)+ 11.5+10.2$

The radius of semicircle is

$r=8/2=4\ yd$

substitute

$P=(3.14)(4)+2(15.2)+ 11.5+10.2=64.66\ yd$

Part B) What is the exact area of the concrete region?

we know that

The area of the composite figure is equal to the area of semicircle plus the area of rectangle plus the area of triangle

$A=\frac{1}{2} \pi r^{2} +(15.2)(8)+\frac{1}{2}(10.2)(8)$

The radius of semicircle is

$r=8/2=4\ yd$

$A=\frac{1}{2} \pi (4)^{2} +(15.2)(8)+\frac{1}{2}(10.2)(8)$

$A=8\pi+121.6+40.8$

$A=(8\pi+162.4)\ yd^{2}$

5 0

4 years ago

BRAINLIEST IF CORRECT AND EXPLANATION <br> Solve each equation in the interval [0, 2pi)

victus00 [196]

Answer: $\frac{\pi}{2}, \ \frac{5\pi}{4}, \ \frac{3\pi}{2}, \ \frac{7\pi}{4}$

We can write the four solutions as: pi/2, 5pi/4, 3pi/2, 7pi/4

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Work Shown:

$\sqrt{2}\cot(x)\sin(x)+\cot(x)=0\\\\\cot(x)\left(\sqrt{2}\sin(x)+1\right)=0\\\\\cot(x)=0 \ \text{ or } \ \sqrt{2}\sin(x)+1=0\\\\\frac{\cos(x)}{\sin(x)}=0 \ \text{ or } \ \sqrt{2}\sin(x)=-1\\\\\cos(x)=0*\sin(x) \ \text{ or } \ \sin(x)=\frac{-1}{\sqrt{2}}\\\\\cos(x)=0 \ \text{ or } \ \sin(x)=\frac{-\sqrt{2}}{2}\\\\$

Use the unit circle or reference sheet to find that $\cos(x)=0$ leads to $x = \frac{\pi}{2} \ \text{ and } \ x = \frac{3\pi}{2}$ when working with the interval [0,2pi)

Also, use of the unit circle would show that $\sin(x)=\frac{-\sqrt{2}}{2}$ leads to $x = \frac{5\pi}{4} \ \text{ and } \ x = \frac{7\pi}{4}$ when working with the interval [0,2pi)

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Overall, the four solutions on the interval [0, 2pi) are

$\frac{\pi}{2}, \ \frac{5\pi}{4}, \ \frac{3\pi}{2}, \ \frac{7\pi}{4}$

To verify these solutions, plug them in one at a time into the original equation. You should end up with 0 = 0 after simplifying. Make sure your calculator is in radian mode.

3 0

3 years ago

Which table does NOT represent a function?

Anna35 [415]

D because some of the inputs have the same output therefor it is not a function

4 0

3 years ago

Read 2 more answers