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Gnoma [55]
3 years ago
11

Viet Cong was the military force for

Mathematics
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

d.i think d is the correct answer

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Transversal cuts parallel lines and at points X and Y respectively. The point nearest to C is X, and the point nearest to D is Y
hammer [34]

Answer:  The answer is (B) ∠SYD.


Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.

We are given four angles, out of which one should be chosen which is congruent to ∠CXP.

The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.

For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.

Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.

Thus, we have

∠CXP ≅ ∠SYD.

So, option (B) is correct.

5 0
3 years ago
I’m not sure on how to do this so could you show me step by step?
likoan [24]

Answer:

yes

Step-by-step explanation:

So the circumfrehce of a circle is basically the perimiter of the circle. Let me help with number 1. We need to find the radius. In order to do tuis we divide 6 in half giving us 3. Then we plug in 3 into the circumfrence formula (Pi times the radius multiplied by 2). So it would be 3.14*3*2. The answer for number 1 is 18.85

5 0
3 years ago
9. Write the missing addend. 46 + = 52​
Alex73 [517]

Answer:

6

Step-by-step explanation:

To find the missing number, subtract: 52 - 46 = 6

3 0
2 years ago
Read 2 more answers
A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de
strojnjashka [21]

Answer:

a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

a= μ-3.16*σ , b= μ+3.16*σ

b) P(Y≥ μ+3*σ ) ≥ 0.90

b= μ+3*σ

Step-by-step explanation:

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90  →  1- σ²/(σ²+λ²)=  1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

5 0
3 years ago
One hundred twenty-three and thirty hundreths. in decimal form
Doss [256]

Answer:

123.030

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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