Hello there.
<span>If we increase the force applied to an object and all other factors remain the same that amount of work will
</span><span>C. Increase
</span>
Answer: You do not specify what is being asked for. ∆E? ∆H?
∆E = (430 - 238) J = 192 J
∆H = 430 J
Explanation:
If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.
Therefore ∆H = 430 J
If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w
The question states that 238 J of work are done AND the system expanded
(work is negative because expansion means work is done BY the system, releasing energy/heat... Conversely, if the system were compressed, work is done ON the system, absorbing heat/energy)
Therefore, ∆E = (430 - 238) J = 192 J
Answer:
Part a)
Part b)
North of East
Explanation:
Speed of train towards East = 60 km/h
displacement towards East is given as
now it turns towards 50 degree East of North
so its distance is given as
then finally it moves towards west for 50 min
Now the total displacement of the train is given as
now total time duration of the motion is given as
now average velocity is given as
Part a)
magnitude of the average velocity is given as
Part b)
Direction of the velocity is given as
North of East
Answer:
Quantity of charge = 80 Coulombs
Explanation:
Given the following data;
Current = 2 A
Time = 40 seconds
To find the amount of charge flowing through the light bulb;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
Quantity of charge = 2 * 40
Quantity of charge = 80 Coulombs
