The changes in internal energy of the system <u>75.1 J.</u>
The internal energy of a thermodynamic system is the total energy contained in it. It is the energy required to create or prepare a system in a given internal state and includes contributions of potential energy and internal kinetic energy.
Calculation:
Internal energy = 162.4 j - work done
= 162.4 j - 87.3 j
=<u> 75.1 J</u>
<u />
Internal energy, in thermodynamics, is the property or state function that defines the energy of matter in the absence of capillary action or external electric, magnetic, or other fields.
Internal energy is the microscopic energy contained in the matter given by the random and disordered kinetic energy of the molecules. It also includes the potential energy between these molecules and the nuclear energy contained in the atoms of these molecules.
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Answer:
binomial nomenclature.
Explanation:
This means that an organism's scientific name is a combination of two terms.
The first is the name of the organism's genus, and the second is the name of the organism's species
together the genus and the species create the name of a single organism.
The momentum of a neutron p = 586.25 kg m / s.
<u>Explanation:</u>
The product of mass and the velocity gives the momentum of an object and it is a vector quantity. It is denoted by the letter p. The unit of momentum is kilogram meter per second (or) kg m / s.
Given mass m = 1.675 
10, velocity v = 3.500 10
Momentum, p = mv
where m represents the mass,
v represents the velocity.
momentum p = (1.675 10) (3.500 10)
momentum p = 586.25 kg m / s.
Answer:
The law of conservation of momentum states that, in the absence of an external force, the momentum of a system remains unchanged.
Explanation:
FOCAL LENGTH = 9.5cm
i° e° d°
30 43 69
40 41 61
45 39 56
50 37 48
65 41 37
plot a graph of d° against i°
from the graph Determine;
(i) the minimum deviation and the corresponding angle of incidence
(ii) the maximum deviation and the corresponding angle of incidence
n=sin(A+D÷2)÷(sinA÷2)
Determine the error in n and explain why it is not advisable to use small values of i° in performing this experiment.
