That crowding resulted in pathological behaviour – in rats and by extension in humans
To solve this problem we will use the general system of simple harmonic movement and compare this structure with the given value. From this equation we can find the phase. Our given value is
Data:
t = 2 s
The expression given from the theory for the harmonic movement is:
Where,
= Phase Angle
A = Amplitude
Here the Phase angle is given as
Comparing we have,
Replacing the time of t, we have that
Therefore the phase of motion at t=2s is
I think the answer is c. the more characteristics they have in common. Sorry if wrong.
Answer:
The acceleration of the centre of mass of spool A is equal to the magnitude of the acceleration of the centre of mass of spool B.
Explanation:
From the image attached, the description from the complete question shows that the two spools are of equal masses (same weight due to same acceleration due to gravity), have the same inextensible wire with negligible mass is attached to both of them over a frictionless pulley; meaning that the tension in the wire is the same on both ends.
And for the acceleration of both spools, we mention the net force.
The net force acting on a body accelerates the body in the same direction as that in which the resultant is applied.
For this system, the net force on either spool is exactly the same in magnitude because the net force is a difference between the only two forces acting on the spools; the tension in the wire and their similar respective weights.
With the net force and mass, for each spool equal, from
ΣF = ma, we get that a = ΣF/m
Meaning that the acceleration of the identical spools is equal also.
Hope this Helps!
Translating the first sentence into equation we get, t = k(1/h)
where t is time in seconds, k is the constant and h is the horsepower. Substituting
the values in the equation we have, 12s = k(1/200) we have a k = 2400 seconds –
hp. To get the time at 240 hp we use the equation above and the constant, we
get, t = (2400 seconds-hp)(1/240hp) t = 10seconds.