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Dima020 [189]
3 years ago
10

Which observational tool helped astronomers Arno Penzias and Robert Wilson discover the existence of the cosmic microwave backgr

ound (CMB)?
Physics
1 answer:
Softa [21]3 years ago
4 0
<span>In 1964, while experimenting with the Holmdel Horn Antenna, which was used as a radio telescope, Penzias and Wilson accidentally discovered the microwave background radiation that exists universally. The Holmdel Horn Antenna was used to support the "Big Bang Theory" as opposed to the "Steady State Theory".</span>
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Calculate the tangential speed of a yo-yo twirled at the end of a 4 meter long string at 2 revolutions per second.
Oliga [24]

Answer: 50 m/s

Explanation: speed v = 2· pi·n·r = 2· 3.14· 2 s^-1· 4 m

8 0
3 years ago
Truck drivers probably cannot see your vehicle if____.
laiz [17]
Answer Is Tailgating
6 0
3 years ago
How are the different firework shapes produced
AleksAgata [21]

To create the shapes, stars are arranged on a piece of cardboard in the desired configuration. If the stars are placed in a smiley face pattern on the cardboard, for example, they will explode into a smiley face in the sky. In fact, you may see several smiley faces in the sky at one time.

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8 0
3 years ago
A spring is stretched from x=0 to x=d, where x=0 is the equilibrium position of the spring. It is then compressed from x=0 to x=
VARVARA [1.3K]

Answer:

The same amount of energy is required to either stretch or compress the spring.

Explanation:

The amount of energy required to stretch or compress a spring is equal to the elastic potential energy stored by the spring:

U=\frac{1}{2}k (\Delta x)^2

where

k is the spring constant

\Delta x is the stretch/compression of the spring

In the first case, the spring is stretched from x=0 to x=d, so

\Delta x = d-0=d

and the amount of energy required is

U=\frac{1}{2}k d^2

In the second case, the spring is compressed from x=0 to x=-d, so

\Delta x = -d -0 = -d

and the amount of energy required is

U=\frac{1}{2}k (-d)^2= \frac{1}{2}kd^2

so we see that the amount of energy required is the same.

7 0
3 years ago
How much work is done if 10 N is applied to a 5kg object for 10 meters if there is an opposing force of 5 N
BlackZzzverrR [31]

Answer:

50 J

Explanation:

The net force acting on the box is given by the algebraic sum of the two forces, so:

F=10 N -5 N = 5 N

The net work done on the box is equal to (assuming the net force is parallel to the displacement of the object)

W=Fd

where

F = 5 N is the net force on the object

d = 10 m is the displacement of the object

Substituting,

W=(5 N)(10 m)=50 J

5 0
3 years ago
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