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LUCKY_DIMON [66]
3 years ago
14

A student reads that soil is formed in part due to the weathering of rocks. The student lists methods in which rocks break down

in a chart, as shown.
Weathering of Rocks
1. Acid rain dissolves rock elements
2. Temperature fluctuations cause cracks and fissures in rocks
3. Animals break apart rocks when forming underground burrows.
4. Plant roots apply pressure on rocks
which are accurate methods of the weathering of rocks?
1 and 2 only
3 and 4 only
1.2 and 4 only
1.2.3. and 4
Physics
1 answer:
Fittoniya [83]3 years ago
3 0
The answer is 1,2,3 and 4
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What is the formula that describes the magnitude of impulse on an object?
vladimir1956 [14]

Answer:

Option C.

Impulse = mass × change in velocity

Explanation:

Impulse is defined by the following the following formula:

Impulse = force (F) × time (t)

Impulse = Ft

From Newton's second law of motion,

Force = change in momentum /time

Cross multiply

Force × time = change in momentum

Recall:

Impulse = Force × time

Thus,

Impulse = change in momentum

Recall:

Momentum = mass x velocity

Momentum = mv

Chang in momentum = mass × change in velocity

Change in momentum = mΔv

Thus,

Impulse = change in momentum

Impulse = mass × change in velocity

8 0
3 years ago
(Please help, will give thanks + brainliest answer)
Bond [772]

Answer:

A) 1.9m/s

Explanation:

Use the equation v=d/t

The time is 10 seconds. The distance is more complicated because it’s a circle so u use the equation for circumference C=2•pi•r. So you just do the circumference over time and get the answer. Hope this helps

8 0
4 years ago
The mysterious visitor that appears in the enchanting story The Little Prince was said to come from a planet that "was scarcely
FromTheMoon [43]

Answer:

Part a)

g = 1 \times 10^{-5} m/s^2

Part b)

v = 0.011 m/s

Explanation:

Part a)

As we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

g = \frac{G(\frac{4}{3}\pi R^3 \rho)}{R^2}

g = \frac{4}{3}\pi \rho G R

now we know that

\rho = \frac{M}{\frac{4}{3}\pi R^3}

\rho = \frac{5.98 \times 10^{24}}{\frac{4}{3}\pi (6.37 \times 10^6)^3}

\rho = 5523.2 kg/m^3

now we have

g = \frac{4}{3}\pi (5523.2) (6.67 \times 10^{-11})(6.5)

g = 1 \times 10^{-5} m/s^2

Part b)

As we know that the escape speed is given as

v = \sqrt{\frac{2GM}{R}}

v = \sqrt{2gR}

v = \sqrt{2(1\times 10^{-5})(6.5)}

v = 0.011 m/s

8 0
3 years ago
I don’t know if I did these rights someone check them or give me the answers? I know the photo has some stuff cut off but you ca
Nana76 [90]

I can’t read some of your work

3 0
3 years ago
A weather balloon is partially inflated with helium gas to a volume of 2.0 m³. The pressure was measured at 101 kPa and the temp
Yanka [14]

Answer:

4.7 m³

Explanation:

We'll use the gas law P1 • V1 / T1 = P2 • V2 / T2

* Givens :

P1 = 101 kPa , V1 = 2 m³ , T1 = 300.15 K , P2 = 40 kPa , T2 = 283.15 K

( We must always convert the temperature unit to Kelvin "K")

* What we want to find :

V2 = ?

* Solution :

101 × 2 / 300.15 = 40 × V2 / 283.15

V2 × 40 / 283.15 ≈ 0.67

V2 = 0.67 × 283.15 / 40

V2 ≈ 4.7 m³

7 0
2 years ago
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