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2 years ago

Which number could replace the to make this number sentence true? 27 > + 8

1 answer:

3 0

Using a sample inequality, take 35> ? + 3. Making that ?=x, we have 35 > x+3. Subtracting 3 from both sides, we get 32 > x. Therefore, as long as 32 is greater than x, any value replacing x is fine.

I challenge you to apply this strategy to this problem! Good luck, and feel free to ask with any questions!

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Simplifying by adding, subtracting, multiplying, or dividing: (2/3)-(2/5)

Volgvan

The answer is 4/15 or .26 with the 6 repeating forever.
Explanation: Least common multiple of 3 and 5 is 15. 2*5=10, 2*3=6. 10/15-6/15=4/15.

8 0

3 years ago

SportsBounceCo makes only boxes that have sides that are measured in whole inches, like the boxes you have been describing so fa

stepan [7]

Answer:

Step-by-step explanation:

Look at the surface area of the box formular : S = 2lw + 2lh + 2wh

When l : length. w: with and h: hight

As we often considered strange, you can always multiply a whole number by a whole number and always get a whole number, and there is no decimal number about the 3 dementions like the boxes you have been describing so far. So It is impossible.

6 0

2 years ago

Attachment below <br> algebra helppppp

yKpoI14uk [10]

Answer: second option.

Step-by-step explanation:

In order to solve this exercise, it is necessary to remember the following properties of logarithms:

$1)\ ln(p)^m=m*ln(p)\\\\2)\ ln(e)=1$

In this case you have the following inequality:

$e^x>14$

So you need to solve for the variable "x".

The steps to do it are below:

1. You need to apply $ln$ to both sides of the inequality:

$ln(e)^x>ln(14)$

2. Now you must apply the properties shown before:

$(x)ln(e)>ln(14)\\\\(x)(1)>2.63906\\\\x>2.63906$

3. Then, rounding to the nearest ten-thousandth, you get:

$x>2.6391$

3 0

2 years ago

Why is 21 over 30 bigger than 2 over 3?

Nikitich [7]

21/30 simplifies to 2.1/3 so it's a little bit bigger

3 0

3 years ago

Read 2 more answers

What are the solutions of 3x^2-x+4=0

guajiro [1.7K]

3x² -x+4=0

We can use quadratic formula
a=3, b= -1, c=4
$x= \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} 
\\ \\ x= \frac{1+/- \sqrt{1-4*3*4} }{2*3} 
\\ \\ x = \frac{1+/- \sqrt{-47} }{6} 

This equation does not have real roots, it has only 2 imaginary roots.$

$x= \frac{1+ \sqrt{47}i }{6} 
\\ \\ x= \frac{1- \sqrt{47}i }{6}$

6 0

3 years ago