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4 years ago

2.86 = ? Tenths + 6 hundredths

1 answer:

8 0

2.86
= 28 tenths + six hundreths.

(The number directly after the decimal point is an hundreth)
Since there is a 2.0 (twenty tenths), the answer is:

20+8 = 28 tenths.

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Approximately how many hours would someone who earns $7.51 per hour have to work to earn $202.85? 27 30 35 37

DerKrebs [107]

1 hr = 7.51

202.85/7.51= 27.01 hours

5 0

3 years ago

Read 2 more answers

Nicole got a prepaid debit card with $25 on it. For her first purchase with the card, she bought some bulk ribbon at a craft sto

vagabundo [1.1K]

Answer:

34 yards of ribbon

Step-by-step explanation:

If you will subtract the $17.52 to $25 you will get 7.48 then 7.48 divide to .22 you will get 34 as the answer

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3 years ago

What is four million,nine hundred thirty-five in standard form

Bad White [126]

4,000,000,39

there you go!

4 0

3 years ago

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Evaluate the summation from n equals 1 to infinity of the quotient of 3 and 2 raised the quantity n minus 1 power

Shalnov [3]

Answer:

3*∑ (1/2)^n = 6

Step-by-step explanation:

We have the summation from n = 1 to n = ∞, for:

∑ 3/(2)^(n - 1)

We know that the summation between k = 0, and k = N - 1 for:

∑ r^k = (1 - r^N)/(1 - r)

if we have the summation between k = 0 and k = ∞ - 1 = ∞

(here we used that ∞ is really big, then ∞ - 1 = ∞)

In the numerator we will have the term r^∞, if 0 < r < 1, then r^∞ = 0.

Then if we assume that 0 < r < 1 we can write:

∑ r^k = 1/(1 - r)

In our case, we can rewrite our summation as:

3*∑ (1/2)^n

for n = 0 to n = ∞

You can see that i changed the limits for n, this does not really matter because we are summing between a number and infinity, the only thing you need to take care is that now the power is n, instead of (n - 1)

Then we have r = (1/2) which is clearly smaller than 1.

then (1/2)

Then this summation is equal to:

3*∑ (1/2)^n = 3*( 1/(1 - 1/2)) = 3*( 1/( 2/2 - 1/2)) = 3*( 1/(1/2)) = 3*2 = 6

3*∑ (1/2)^n = 6

5 0

3 years ago

Find the first four terms of the sequence<br> An=2a n-1,where a1=3

yKpoI14uk [10]

The first four terms of the sequence are 3 , 6 , 12 , 24

Step-by-step explanation:

We need to find the first four terms of the sequence $a_{n}=2a_{n-1}$