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kondor19780726 [428]
3 years ago
6

During the phosphatase experiment you will use several different ph buffers. the ph value depends upon combing various ratios of

0.1m citric acid and 0.2m sodium phosphate dibasic (na2hpo4, m.w. = 142 g/mole). describe how you would make 300 ml of 0.2m sodium phosphate dibasic given a 500g bottle of na2hpo4. include the type and sizes of any measuring vessels that you use to make the solution.
Chemistry
1 answer:
Elan Coil [88]3 years ago
7 0
First calculate mass of sodium hydrogen phosphate (Na₂HPO₄) needed for solution:
n(Na₂HPO₄) = V(Na₂HPO₄) · c(Na₂HPO₄)
n(Na₂HPO₄) = 0,3 dm³ · 0,2 mol/dm³
n(Na₂HPO₄) = 0,06 mol
m(Na₂HPO₄) = 0,06 mol · 142 g/mol
m(Na₂HPO₄) = 8,52 g.
Measure that mass on scale using spoon and beaker. Than dissolve salt in beaker with distilled <span>water and pour that solution in volumetric flask (size 300 mL), pour </span>distilled water to graduation<span> mark.</span>
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