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3 years ago

Which statement best describes the difference between strong nuclear forces and weak nuclear forces? (2 points)

2 answers:

8 0

Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for holding atoms' nucleus together. Both forces are actually very strong, and are only felt at very short distances. They are 2 of the 4 fundamental forces that govern all matter.

san4es73 [151]3 years ago

8 0

Answer:

Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for holding atoms' nucleus together

Explanation:

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A car starts from rest and experiences a constant acceleration of 5 m/s2 until it reaches a speed of 650 meters

Zigmanuir [339]

Answer: Time.

Explanation:

Hey there!!!

The reason is,

According to the question we have,

Initial velocity = 0m/s { as it starts from rest}.

Final velocity = 650 m/s

acceleration = 5m/s^2.

Looking on this formula,

$a = \frac{v - u}{t}$

Where "v" represents final velocity, "u" represents initial velocity and "a" represents acceleration. We dont have is time "t".

So, it's obvious that tine is an unknown variable.

Hope it helps...

8 0

3 years ago

Question 29 of 43

liraira [26]

I agree with the first responses

3 0

3 years ago

A soccer player takes a free kick from a spot that is 20 m from the goal. The ball leaves his foot at an angle of 38 ∘, and it e

Sergio039 [100]

This dude can kick the ball

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3 years ago

A ball is thrown straight up. It passes a 2.00-m-high window 7.50 m off the ground on its path up and takes 0.312 s to go past t

marta [7]

Answer:

Explanation:

Given that

The window height is 2m

And the window is 7.5m from the ground

Then the total height of the window from the ground is 7.5+2=9.5m

It takes the ball 0.32sec travelled pass the window.

When the ball get to the window, it has an initial velocity (u') and when it gets to the top of the window it has a final velocity ( v')

Now using the equation of free fall during this window travels

S=ut-½gt² against motion.

S=2, g=9.81, t=0.32sec

Then,

S=u't-½gt²

2=u'×0.32-½×9.81×0.32²

2=0.32u'-0.5023

2+0.5032=0.32u'

Then, 0.32u'=2.5032

u'=2.5032/0.32

u'=7.82m/s

This is the initial velocity as the ball got the the window

Now, let analyse from the window bottom to the ground which is a distance of 7.5m

Using the equation of free fall again

v²=u²-2gH

In this case the final velocity (v) is the velocity when the ball reach the bottom of the window i.e u'=7.82m/s,

While u is the original initial velocity from the throw of the ball

Then,

u'²=u²-2gH

7.82²=u²-2×9.81×7.5

61.146=u²-147.15

61.146+147.15=u²

Then, u²=208.296

So, u=√208.296

u=14.43m/s

The initial velocity of the ball form the throw is 14.43m/s

6 0

3 years ago

Something about the earth's surface (land or water) changes

Leokris [45]

I would say land changes.

6 0

3 years ago