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yaroslaw [1]
4 years ago
11

How many moles of NH3 can be produced from 15.0 mol of H2 and excess of N2? express your answer numerically in moles

Chemistry
1 answer:
STALIN [3.7K]4 years ago
3 0

Answer:

zhzhsjwuwusysushshsjshshsbshshdhdhshdhdbdbbdf

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Calculate the number of moles in 180 grams of Magnesium Chloride
BabaBlast [244]

Answer:

0.5 moles

Explanation:

u will get molar mass = 95.2 I think

then number of moles = molar mass÷ mass

=95.2÷180=0.5

3 0
3 years ago
Ch
Aleksandr-060686 [28]

Answer:

Hello There!!

Explanation:

I believe the answer is how fast the molecules are vibrating.

hope this helps,have a great day!!

~Pinky~

8 0
3 years ago
The current global population is 7.7 billion people, and the WHO estimates the minimum water need per person per day is 15 L. An
anygoal [31]

Answer:

a) The amount of freshwater available as groundwater, lakes and rivers, does not even reach one day the need for consumption for the current global population.  ( t = 5.489 E-13 day )

b) The annual terrestrial precipitation, reaches to sustain the drinking water needs for the current global population

Explanation:

Let P = 7.7 billion people = 7.7 E12 person

∴ water needed for the total population for one day:

⇒ water amount  = 7.7 E12 person * ( 15 L / person. day ) = 1.155 E14 L H2O /day

⇒ water amount = 1.155 E14 L H2O/day * 1 E1 Km² H2O / L H2O = 1.155 E15 Km² H2O/day * ( 365 day / year ) = 4.216 E17 Km²/year

∴ freshwater available:

freshwater = 6.34 E2 Km² H2O

how long will this water sustain the current population?

⇒ t = 6.34 E2 Km² * day / 1.155 E15 Km² = 5.489 E-13 day

this amount of freshwater does not even meet the need of the current global population.

∴ the annual terrestrial precipitation (Py) = 505000 Km³/year..........from literature

⇒ Py = 505000 Km³ H2O/year * ( 1000 m/Km )³ * ( 1000L/m³ )

⇒ Py = 5.05 E17 L H2O/year * ( 1 E1 Km² / L ) = 5.05 E18 Km² H2O/year

⇒ Py > water amount

the annual terrestrial precipitation of water, reaches to sustain the drinking water needs.

4 0
3 years ago
Calculate the percentage by mass of oxygen in Al2(SO4)3 (Al=27, S=32,O= 16) PLEASE SHOW FULL WORKING​
White raven [17]

Answer:

There is 61.538% oxygen in Al2(SO4)3.

Explanation:

Wt Of oxygen in the compound = 12*16 = 192 amu.

Total Wt. Of the compound = 2*12+3*32+12*16 = 312 amu.

Thus, percent of oxygen = Wt of oxygen/total Wt. Of compound *100

= 192/312 * 100=61.538 %

6 0
3 years ago
Read 2 more answers
What is in the nucleus of the atom​
salantis [7]

Answer:

Umm i dont know but i think atomic nucleus

Explanation:

8 0
3 years ago
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