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bezimeni [28]
3 years ago
10

The hydrogen ion​ concentration, ​[H+​], in a certain cleaning compound is left bracket Upper H Superscript plus Baseline right

bracket equals 3.6 times 10 Superscript negative 11H+=3.6×10−11. Use the formula pH=−log[H+] to find the pH of the cleaning compound.
Chemistry
1 answer:
labwork [276]3 years ago
8 0

<u>Answer:</u> The pH of the cleaning compound is 10.44

<u>Explanation:</u>

pH is defined as the negative logarithm of hydrogen or hydronium ion concentration that are present in a solution.

The equation representing pH of the solution follows:

pH=-\log[H^+]

We are given:

[H^+]=3.6\times 10^{-11}

Putting values in above equation, we get:

pH=-\log(3.6\times 10^{-11})

pH=10.44

Hence, the pH of the cleaning compound is 10.44

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Answer:

K = \frac {[Cr_{2}O_{7}^{2-}]}{[CrO_{4}^{2-}]^{2} \cdot [H_{3}O^{+}]^{2}}  

Explanation:  

The equilibrium constant for a given reversible aqueous reaction is defined by the product ratio of the concentrations between the products and reactants:      

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K = \frac {[products]^{p}}{[reactants]^{r}} = \frac {[C]^{c} \cdot [D]^{d}}{[A]^{a} \cdot [B]^{b}}  

<em>where K: is the equilibrium constant, [C] and [D]: are the product concentrations, [A] and [B]: are the reactant concentrations and a,b,c,d: are the stoichiometric coefficients from the reaction.   </em>

Therefore, based on the definition the equilibrium constant of our reaction is:    

2CrO₄²⁻(aq) + 2H₃O⁺(aq) ⇄ Cr₂O₇²⁻(aq) + 3H₂O(l)

K = \frac {[Cr_{2}O_{7}^{2-}]}{[CrO_{4}^{2-}]^{2} \cdot [H_{3}O^{+}]^{2}}  

Generally, the water concentration is omitted from the expressions.

I hope it helps you!

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