All categories

3 years ago

Evaluate j/k - 0.2k when j = 25 and k = 5

Mathematics

2 answers:

andrew-mc [135]3 years ago

6 0

Answer:

Step-by-step explanation:

Step 1: Set j to 25 and k to 5

j/k - 0.2k

(25)/(5) - 0.2(5)

5 - 1

4

Answer: 4

olganol [36]3 years ago

6 0

Answer: 4.8

Step-by-step explanation:

J/K is dividing. 25 divided by 5 is 5 and subtract 0.2 from it

You might be interested in

A glacier moves about 3 inches every 9 hours. At this rate, about how far does the glacier move in 36 hours?

MrRa [10]

Answer:

The answer is 12

Step-by-step explanation:

36/9=4

4x3=12

7 0

3 years ago

Read 2 more answers

israel started to solve a radical equation in this way: square root of x plus 6 − 4 = x square root of x plus 6 − 4 4 = x 4 squa

agasfer [191]

Lets solve our radical equation $\sqrt{x+6}-4=x$ step by step.

Step 1 add 4 to both sides of the equation:

$\sqrt{x+6} -4+4=x +4$

$\sqrt{x} +6=x+4$

Step 2 square both sides of the equation:

$\sqrt{x+6} =x+4$

$\sqrt{x+6}^2 =(x+4)^2$

$x+6=(x+4)^2$

Step 3 expand the binomial in the right hand side:

$x+6=x^2+8x+16$

Step 4 simplify the expression:

$0=x^2+8x-x+16-6$

$x^2+7x+10=0$

Step 5 factor the expression:

$(x+2)(x+5)=0$

Step 6 solve for each factor:

$x+2=0$ or $x+5=0$

$x=-2$ or $x=-5$

Now we are going to check both solutions in the original equation to prove if they are valid:

For $x=-2$

$\sqrt{x+6}-4=x$

$\sqrt{-2+6}-4=-2$

$\sqrt{4}-4=-2$

$2-4=-2$

$-2=-2$

The solution $x=2$ is a valid solution of the rational equation $\sqrt{x+6}-4=x$ .

For $x=-5$

$\sqrt{x+6}-4=x$

$\sqrt{-5+6}-4=-5$

$\sqrt{1}-4=-5$

$1-4=-5$

$-3\neq -5$

Since -3 is not equal to -5, the solution $x=-5$ is not a valid solution of the rational equation $\sqrt{x+6}-4=x$ ; therefore, $x=-5$ is an extraneous solution of the equation.

We can conclude that even all the algebraic procedures of Israel are correct, he did not check for extraneous solutions.

An extraneous solution of an equation is the solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation. Is worth pointing out that extraneous solutions are particularly frequent in rational equation.

8 0

3 years ago

Why can I not post a question that it at a certain number of letters?

juin [17]

Answer:

I really dont know

Step-by-step explanation:

Maybe the server thinks ur doing sum bad but i dont know

4 0

3 years ago

Read 2 more answers

Which one of these four sets of side lengths will form a right triangle?