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nirvana33 [79]
3 years ago
6

A recent national survey found that high school students watched an average (mean) of 6.8 movies per month with a population sta

ndard deviation of 1.8. The distribution of number of movies watched per month follows the normal distribution. A random sample of 36 college students revealed that the mean number of movies watched last month was 6.2. At the 0.05 significance level, can we conclude that college students watch fewer movies a month than high school students?
Mathematics
1 answer:
Margaret [11]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that x = no of movies high school students watched is N(6.8, 1.8)

Sample size = 36 and hence std error = 1.8/6 = 0.3

H_0: x bar = 6.8\\H_a: x bar < 6.8\\

(two tailed test)

Mean difference = 6.2-6.8 = -0.6

Test statistic z = -0.6/0.3= -2

p value = 0.02275

Since p <0.05 we reject H0.

There is evidence to show that college students watch fewer movies a month than high school students

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Question:

Yuet solved the equation 6a - 2b = 12 for a.

Her steps are shown below.

1. Subtract 2b: 6a = 12 - 2b

2. Divide by 6: a = 2 - \frac{b}{3}

Answer:

In step 1 she needed to add 2b to both sides of the equation.

Step-by-step explanation:

Given:

The above steps shows how Yuet solved an equation

Required:

True statement about Yuet's work

The implication of the statement is to state what Yuet should have done instead of what she did.

In step 1, she subtracted 2b from both sides of the equation; this is wrong.

Instead of subtracting, she ought to add 2b to both sides of the equation.

The correct steps and result is as follows:

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