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DedPeter [7]
3 years ago
14

Ms. Blankenship had $80 to purchase school supplies for her class. She bought 32 glue sticks and 32 boxes of crayons. Each glue

stick cost $1.40, and each box of crayons cost $0.59. How much money did Ms. Blankenship have left after these purchases? F $16.32 G $18.88 H $63.68 J $35.20
Mathematics
2 answers:
anzhelika [568]3 years ago
7 0
All 32 glue sticks cost 44.80 dollars and all the crayon boxes cost 18.88 dollars. She spent 63.68 dollars. She has 16.32 dollars left.
babymother [125]3 years ago
4 0
First you have to multiply 32 times 1.40 to get $44.80 Then you have to times 32 times 0.59 which equals $17.92 44.80 plus 17.92 equals $62.72. 80 minus 62.72 equals 17.28.  $17.28 is your answer <span />
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Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an m\times n matrix.  Let T :U\to V  be the corresponding linear transformationover the field F and \theta be identity vector in V. Now if x\in Ker( T)\implies T(x)=\theta.

(1) The kernel of a linear transformation is a vector space : True.

Let x,y\in Ker( T), then,

T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)

hence the kernel is closed under addition.

Let \lambda\in F, x\in Ker( T), then

T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta

\lambda x\in Ker(T) and thus Ket(T) is closed under multiplication

Finally, fore all vectors u\in U,

T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta

\implies \theta\in Ker(T)

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is \mathbb R^m : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in \mathbb R^m

: False

The null space that is dimension of solution space of an m x n matrix is always in \mathbb R^n.

(4) The column space of A is the range of the mapping x\to Ax

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0
3 years ago
Question 1 Part B (3 points): Using the GCF that you chose in part A, factor that GCF out of the polynomial:
Aleks [24]

The factor of the polynomial 18x³ + 6x²y - 9x² - 3xy will be 3x(6x² - 2xy - 3x - y). Then the correct option is C.

<h3>What is a factorization?</h3>

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

The polynomial is given below.

⇒ 18x³ + 6x²y - 9x² - 3xy

Then the factor of the polynomial will be

⇒ 18x³ + 6x²y - 9x² - 3xy

⇒ 3x(6x² - 2xy - 3x - y)

More about the factorization link is given below.

brainly.com/question/6810544

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Gemiola [76]

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Help me with my homework. i will heart correct
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Answer:

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