It would be b. If two numbers are negative and your multiplying them, it would be positive!
Answer:
Randy has eight $5 bills and nine $1 bills
Step-by-step explanation:
Randy needs $50.00
And we know that he his only $1.00 short, so he has $49.00
let's define:
x = number of $1 bills that he has
y = number of $5 bills that he has.
then:
x*$1 + y*$5 = $49
We know that he has one more $1 bills than $5 bills.
we can write this as
x = y + 1
So we have a system of two equations and two variables:
x*$1 + y*$5 = $49
x = y + 1
First we can see that the variable "x" is isolated in the second equation, now we can replace that in the other equation:
x*$1 + y*$5 = $49
(y + 1)*$1 + y*$5 = $49
now we can solve this for y.
y*$1 + $1 + y*$5 = $49
y*($1 + $5) = $49 - $1 = $48
y*$6 = $48
y = $48/$6 = 8
He has 8 $5 bills
and we know that:
x = y + 1
x = 8 + 1 = 9
he has 9 $1 bills.
Answer:
There is 666.66666666 non fic, and 1333.33333334 fic
Step-by-step explanation:
Answer:
5000
Step-by-step explanation:
hmu if you need more help! :D
The numbers are 3 and 7
Step-by-step explanation:
Let the first number be x and the second number be y
Then according to given statement
One number added to three times another number is 24
x+3y=24 Eqn 1
Five times the first number added to three times to other number is 36
5x+3y=36 Eqn 2
Subtracting Equation 1 from equation 2

Dividing both sides by 4

Putting x=3 in equation 1

Dividing both sides by 3

Hence,
The numbers are 3 and 7
Keywords: Linear equations, Variables
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