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Savatey [412]
3 years ago
5

Would be great if someone explained this

Mathematics
1 answer:
sasho [114]3 years ago
5 0

A. 2.

A radical is an expression which implies the use of a root.

There are three components of a radical expression:

(i) The root "√".

(ii) The radicand √"a".

(iii) The degree or index of the radical \sqrt["n"]{a}, when index of the radical is not shown then it understood to be a index of 2.

The index is the number used to indicate the degree of the root.

For the example \sqrt{10}, 10 is the radican and the index is not shown so it understood is 2.

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Please help asap 25 pts + brainliest to right/best answer
patriot [66]

Look at the picture.

<h3>Answer: d. (-3, 1)</h3>

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4 years ago
I WILL MARK AS BRAINLIEST! Simplify
aev [14]
A. 40
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Read 2 more answers
In 1990, Dawn gross pay was $48,000.
forsale [732]

A. Dawn's gross monthly pay is<em> $4,000</em> ($48,000/12).

B. The month that Dawn hit her maximum taxable Social Security Income is May (5 months from January to May).

C. In February, 1978, Dawn paid <em>$260</em> in Social Security Tax.

D. In May, 1978, Dawn paid <em>$110.50</em> in Social Security Tax, which represented the balance.

E. In November, 1978, Dawn paid <em>$0</em> in Social Security Tax because by May she had completely paid the maximum Social Security Tax of $1,150.50.

<h3>Data and Calculations:</h3>

Gross earnings in 1990 = $48,000

Maximum taxable income in 1990 = $17,700

Social Security Tax Rate = 6.5%

Gross monthly pay = $4,000 ($48,000/12)

Monthly Social Security Tax = $260 ($4,000 x 6.5%)

Total Social Security Tax = $1,150.50 ($17,700 x 6.5%)

In 5 months, Dawn would have paid a <em>total of $1,150.50</em> ($260 x 4 + $110.50) in Social Security Tax.

Thus, the total Social Security Tax paid by Dawn in that year was <em>$1,150.50.</em>

Learn more about Social Security Tax here: brainly.com/question/9741758

4 0
2 years ago
Write a quadratic equation given the roots -1/3 and 5, show your work
Travka [436]

\boxed{(x - a)(x - b) = 0}

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

x =  -  \frac{1}{3}  \\ x = 5

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

(x +  \frac{1}{3} )(x -  5) = 0

Here we can convert the expression x+1/3 to this.

x +  \frac{1}{3}  = 0 \\  3x + 1 = 0

Rewrite the equation.

(3x + 1)(x - 5) = 0

Simplify by multiplying both expressions.

3 {x}^{2}  - 15x + x - 5 = 0 \\ 3 {x}^{2}  - 14x  - 5 = 0

<u>Answer</u><u> </u><u>Check</u>

Substitute the given roots in the equation.

3 {(5)}^{2}  - 14(5)  - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0

3( -  \frac{1}{3} )^{2}  - 14( -  \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) +  \frac{14}{3}  - 5 = 0 \\  \frac{1}{3}  +  \frac{14}{3}  -  \frac{15}{3}  = 0 \\  \frac{15}{3}  -  \frac{15}{3}  = 0 \\ 0 = 0

The equation is true for both roots.

<u>Answer</u>

\large \boxed {3 {x}^{2}  - 14x - 5 = 0}

8 0
3 years ago
7 - 12c = 43 show work and check plz
Svetradugi [14.3K]
The answer is -3

-12c = 43 - 7
-12c = 36
÷ -12 ÷-12
c = -3
4 0
3 years ago
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