Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
Answer: The answers is alternate interior angles.
Step-by-step explanation: First of all, the questions marks given in the figure are renamed in the attached figure as (a), (b), (c) and (d).
For (a): Since AC is parallel to A'C' and A'D is a transversal for these two parallel lines, so, ∠CDB' = ∠B'A'C', because these are alternate interior angles.
For (b): Since BC is parallel to B'C' and A'B' is a transversal, so ∠BEB' = ∠A'B'C', because these are alternate interior angles.
For (c): Since AB is parallel to A'B' and AD is a transversal, so ∠BAC = ∠CDB', because these are alternate interior angles.
For (d): Since AB is parallel to A'B' and BE is a transversal, so ∠ABC = ∠BEB', because these are alternate interior angles.
Thus, all the questions marks are the reasons that the given angles are equal because they are alternate interior angles.
Answer:
-4/3
Step-by-step explanation:
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Answer:
y = 0.5x + 5
Step-by-step explanation:
Use the slope formula to find the slope of a line given the coordinates of two points on the line.
The slope formula is:
m =
= 
The coordinates of the first point represent x1 and y1. The coordinates of the second points are x2, y2.
Now let's fill in the formula with the points,
m = 
Solve,
⇒ Y = 9 – 7 = 2
⇒ X = 8 – 4 = 4
m =
= 
Simplify,
⇒ 
Therefore, the Equation of the line is y = 0.5x + 5.