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Anettt [7]
3 years ago
8

Find S15 for the geometric series 72 + 12 + 2 + 1/3 +…

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0
S1 = 72
S2 = 12 = 72*(1/6)
S3 = 2 = 72*(1/6)^2
.
.
.
S15 = 72*(1/6)^14 = 9.18*10^(-10)
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Answer:

Option B k > 0

Step-by-step explanation:

we know that

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we have

3y-2x=k(5x-4)+6\\ \\3y=5kx-4k+6+2x\\ \\3y=[5k+2]x+(6-4k)\\ \\y=\frac{1}{3}[5k+2]x+(2-\frac{4}{3}k)

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Analyze the y-intercept

(2-\frac{4}{3}k) < 0\\ \\ 2 < \frac{4}{3}k\\ \\1.5 < k\\ \\k > 1.5

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so

the solution for k is the interval ------> (1.5,∞)

therefore

must be true

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3 years ago
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