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Andreyy89
3 years ago
11

Simplify 14-2 times 3

Mathematics
1 answer:
kumpel [21]3 years ago
5 0
14 - 6 = 8 this is the answer
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WILL GIVE BRAINLIEST IF CORRECT NOT TOO HARD JUST IN A RUSH!!!!!
STALIN [3.7K]

Answer:

22.5

Step-by-step explanation:

If you divide y/x each ticket costs $2.5, so multiply 2.5x9 and that's your answer. :)

3 0
3 years ago
Which of the following sets is NOT closed under addition.
Veronika [31]

Answer:

Step-by-step explanation:

The odd numbers.

Suppose you have 31 and 27 when you add these two together, you get 58 which is not an odd number.

If you need a more mathematical proof, you could do it this way.

2x+1

2x is even. Anything multiplied by 2 is even. When you add 1 you get an odd number

So continue on

2y + 1 is the other number.

2x + 1 + 2y + 1 = 2(x + y) + 2

2 (x + y ) is even. When you add 2 to it, nothing changes. The result is still even.

7 0
3 years ago
The sequence of 5,8,14,26
omeli [17]
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4 0
3 years ago
Read 2 more answers
in 2009 Larry's gross pay was $275,800 in that year the maximum taxable for Social Security was 118500 and the Social Security w
zysi [14]

Based on the maximum taxable amount for social security in 2009, and the social security tax rate, the social security tax that Larry paid was $7,347.

<h3>How much did Larry pay in social security taxes?</h3>

The total amount paid by Larry as Social security tax can be found as;

= Maximum amount allowable for social security tax x Social security tax rate

The social security tax rate was 6.2% not 62.2%.

The social security tax was therefore:

= 118,500 x 6.2%

= $7,347

Find out more on social security taxes at brainly.com/question/13255138

#SPJ1

3 0
1 year ago
Mel has to put the greatest number of
Dmitry_Shevchenko [17]

Mel should use the least  common multiple to solve the problem

<u>Solution:</u>

Given, Mel has to put the greatest number of bolts and nuts in each box so each box has the same number of bolts and the same number of nuts.  

We have to find that should Mel use the greatest common factor or the least common multiple to solve the problem?

He should use least common multiple.

Let us see an example, suppose 12 bolts and nuts are to be fit in 6 boxes.

Then, if we took H.C.F of 12 and 6, it is 6, which means 6 bolts and nuts in each box, but, after filling 2 boxes with 6 bolts and nuts, there will be nothing left, which is wrong as remaining boxes are empty.

So the remaining method to choose is L.C.M.

Hence, he should use L.C.M method.

6 0
3 years ago
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