AD || BC
<span>• AB = CD </span>
<span>• ∠BAD = ∠CDA (a given condition ∵ ABCD is an isosceles trapezium) </span>
<span>The diagonals AC and BD create two ∆'s: ∆ABD, and ∆ACD </span>
<span>The two ∆'s are congruent (SAS). </span>
<span>(S): AB = CD </span>
<span>(A): ∠BAD = ∠CDA
</span><span>(S): AD = DA (common side) </span>
<span>
The corresponding sides of the two ∆'s, BD and AC, are also congruent. </span>
<span>(the two diagonals of the trapezium/trapezoid)
</span>
The decimal value of 4/11 is 0.36 repeating.
The Answer is x=2 for this problem
