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EleoNora [17]
3 years ago
9

Which best describes the electric field created by a positive charge?

Physics
2 answers:
Aloiza [94]3 years ago
5 0

Answer:

Its rays point away from the charge.

Explanation:

The electric field due to a point charge is given by :

E=\dfrac{kq]{r^2}

Where

k is the electrostatic constant

q is the point charge

r is the distance from charge particle

It is clear that the electric field is directly proportional to the charge and inversely proportional to the distance from charge particle.

There are two types of charged particle i.e. negative and positive charge. For a positive charge, the direction of electric field points away from it and for a negative charge, the direction of electric field points towards it.

Hence, the correct option is (c).

Vlad [161]3 years ago
3 0
Its rays point away from the charge
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6. Dan wants to create acceleration. He
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d. Maintain constant velocity

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A constant velocity leads to no acceleration.

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3 years ago
Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of
xxMikexx [17]

Answer:

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Explanation:

We have given wavelength of the light \lambda =430nm=430\times 10^{-9}m

Velocity of light is equal to v=3\times 10^8m/sec

We have to find the frequency of light

We know that velocity is equal to v=\lambda f, here \lambda is wavelength and f is frequency of light

So frequency of light will be equal to f=\frac{v}{\lambda }=\frac{3\times 10^8}{430\times 10^{-9}}=6.97\times 10^{1}Hz

So frequency of the light will be equal to 6.97\times 10^{1}Hz

5 0
3 years ago
A high-jump athlete leaves the ground, lifting her center of mass 1.8 m and crossing the bar with a horizontal velocity of 1.4 m
Romashka [77]

Answer:

The minimum speed when she leave the ground is 6.10 m/s.

Explanation:

Given that,

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Height = 1.8 m

We need to calculate the minimum speed must she leave the ground

Using conservation of energy

K.E+P.E=P.E+K.E

\dfrac{1}{2}mv_{1}^2+0=mgh+\dfrac{1}{2}mv_{2}^2

\dfrac{v_{1}^2}{2}=gh+\dfrac{v_{2}^2}{2}

Put the value into the formula

\dfrac{v_{1}^2}{2}=9.8\times1.8+\dfrac{(1.4)^2}{2}

\dfrac{v_{1}^2}{2}=18.62

v_{1}=\sqrt{2\times18.62}

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Hence, The minimum speed when she leave the ground is 6.10 m/s.

6 0
3 years ago
A strong man and a weak man are trying to carry a ladder . How should they carry it in such a way that the weak person feels les
dsp73

Answer:

The strong person should carry the ladder at the  front end and the weak person should carry it at the back end.

Explanation:

this is because in such a case the strong person has to pull the ladder whereas the weak person at the back end have to push the ladder. In such case it is easier to push because the weak person can use the force of gravity of his own body for pushing the ladde.

However in case of pulling the ladder one has to overcome his own gravity to pull the heavy object

<u>                                                                                                                                 </u>

<h2><em>I Hope it help you </em></h2>
7 0
3 years ago
Read 2 more answers
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