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EleoNora [17]
3 years ago
9

Which best describes the electric field created by a positive charge?

Physics
2 answers:
Aloiza [94]3 years ago
5 0

Answer:

Its rays point away from the charge.

Explanation:

The electric field due to a point charge is given by :

E=\dfrac{kq]{r^2}

Where

k is the electrostatic constant

q is the point charge

r is the distance from charge particle

It is clear that the electric field is directly proportional to the charge and inversely proportional to the distance from charge particle.

There are two types of charged particle i.e. negative and positive charge. For a positive charge, the direction of electric field points away from it and for a negative charge, the direction of electric field points towards it.

Hence, the correct option is (c).

Vlad [161]3 years ago
3 0
Its rays point away from the charge
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While vacationing in the mountains you do some hiking. In the morning, your displacement is S⃗ morning= (2200 m , east) + (4000
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Answer:

a

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b

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a  = 6562.0 \  m

    The resultant displacement in vertical direction (i.e the altitude change )

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From the question we are told that  

  The displacement in the morning is  S_{morning} =  (2200 \m , east) + (4000\ m\ north) + (100 \ m ,\ vertical)

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Generally the direction west is negative , the direction east is positive

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    (2200 \m , east) +( - 1300\ m ,\ west) = 900 \ m \ east

     (4000\ m\ north)  + (2500 \ m ,\ north) = 6500  \ m ,\ north

     (100 \ m ,\ vertical) - (300\ m ,\ vertical) = -200 \ m

From the above calculation we see that at the end of the hiking the hiker (you) is  200 m below his/her(your) initial position

Generally from Pythagoras theorem , the resultant displacement in the north east direction is

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Generally from Pythagoras theorem , the resultant displacement in vertical direction (i.e the altitude change )

      b = \sqrt{6500^2 +(-200)^2  }

=>   b =6503.1 \  m

   

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