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Ganezh [65]
4 years ago
11

Find the volume of the cone shown below.

Mathematics
2 answers:
Vilka [71]4 years ago
8 0

Answer:

768pi units^3

Step-by-step explanation:

deff fn [24]4 years ago
7 0

Answer:

D

Step-by-step explanation:

the volume (V) of a cone is

V = \frac{1}{3}πr²h

where r is the radius and h the perpendicular height to the base

here r = 12 and h = 16

V = \frac{1}{3}π × 12² × 16 = 768π units³ → D


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Rewrite the exponent as a fraction with postive a positive exponent.<br><br> (-2)^-3
Stella [2.4K]

Answer:

Step-by-step explanation:

The sign minus indicates that the power is located on the denominator

\frac{1}{2^{3} }

4 0
3 years ago
yx is perpendicular to wz at X between W and Z. wxy=zyx and yw=yz Which congruency statements (HL, AAS, ASA, SAS, and SSS) can y
dybincka [34]

Answer:

It is given that , In ΔW X Y, Y X is perpendicular to W Z. Also, y w= w z.

To Prove: ΔW X Y ≅ ΔZ Y X

Proof:

In Δ W X Y and Z Y X

Y X ⊥ W Z→→→→Given

Y W= Y Z→→(Given)

∠YWX=∠YZX→→As, opposite sides of a triangle are equal, so angle opposite to them are equal.

∠YXW=∠YXZ→→Each being 90°

So, ΔYXW≅ΔYXZ→→[AAS]

Also, YX is common sides between two triangles.

ΔYXW≅ΔYXZ→→[HL]

So,the two triangles can be proved congruent by either AAS, or HL.

7 0
3 years ago
F(x)=6x^3 - 3x^2 4x- 15 for x = -3.5
Airida [17]

Answer:

Factor by grouping. (3r + 5)(r-3)

Step-by-step explanation:

8 0
4 years ago
Need help finding the missing angle
lys-0071 [83]

Answer:

Step-by-step explanation:

Sinθ = opp/hyp

Sinθ = 12/13

θ = ArcSin (12/13)

θ =67.38

Let x = adj

Tan (67.38) = 15/x

2.4= 15/x

x2.4= 15

x=6.25

Therefore the missing value  is 6.25

6 0
2 years ago
The data set shows how many points Mark scored in each basketball game he played this season.
algol [13]

Answer:

Kindly check attached picture

Step-by-step explanation:

Given the data :

1,4,4,5,5,7,8,8,10,11,11,11,14,15,16

The median (Q2) :

0.5(n + 1)th value

n = number of observations = 15

0.5(15 + 1)th value = 0.5(16) = 8th observation = 8

Q3:

0.75(n+1)th value = 0.75(16) = 12th observation = 11

Q1 :

0.25(n+1)th value = 0.25(16) = 4th observation = 5

Interquartile range (IQR) = (Q3 - Q1) :

11 - 5 = 6

MINIMUM VALUE IN DATASET = 1

MAXIMUM VALUE IN DATASET = 16

5 0
4 years ago
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