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bekas [8.4K]
3 years ago
11

What is the greatest common factor of 81, 135, and 216?

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0
The greatest common factor is 27. Hope this helps!
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Raffle tickets are being sold for a fundraiser. The function a(n) relates the
Vlada [557]

Answer:

If the function is

A(n) = 4n -25

and we wish to get the inverse function N(a)

We let

A(n) = a

n = N(a)

Plugging in the values

a = 4 N(a) - 25

Arranging the equation:

4 N(a) = a + 25

N(a) = (a + 25) /4

The answer is

N(a) = (a + 25) /4

Step-by-step explanation:

8 0
3 years ago
Subtract 2m – 7q + 5 from 4p + 2q and add your result to 7m² - 3m + 9q – 1
max2010maxim [7]

212134568899999999love is love

7 0
3 years ago
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A patient is instructed to take three 50-mcg tablets of pergolide mesylate (Permax) daily. How many milligrams of the drug would
Black_prince [1.1K]

Answer:

The patient would receive 1.05mg of the drug weekly.

Step-by-step explanation:

First step: How many mcg of the drug would the patient receive daily?

The problem states that he takes three doses of 50-mcg a day. So

1 dose - 50mcg

3 doses - x mcg

x = 50*3

x = 150 mcg.

He takes 150mcg of the drug a day.

Second step: How many mcg of the drug would the patient receive weekly?

A week has 7 days. He takes 150mcg of the drug a day. So:

1 day - 150mcg

7 days - x mcg

x = 150*7

x = 1050mcg

He takes 1050mcg of the drug a week.

Final step: Conversion of 1050 mcg to mg

Each mg has 1000 mcg. How many mg are there in 1050 mcg? So

1mg - 1000 mcg

xmg - 1050mcg

1000x = 1050

x = \frac{1050}{1000}

x = 1.05mg

The patient would receive 1.05mg of the drug weekly.

6 0
3 years ago
This is really confusing
sertanlavr [38]

Answer:

a. Diego

b. Lin

Step-by-step explanation:

a. Diego

b. Lin

It's pretty easy just do some subtraction.

Actually look and pay attention in class this is like grade 1 math.

7 0
2 years ago
Read 2 more answers
Please help!!!!!!
12345 [234]
The area of a circle is:

A=pr^2

You are told r=32 so

A=p32^2

A=1024p u^2
8 0
3 years ago
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