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timurjin [86]
4 years ago
15

HELP ME PLZZ I NEED HELP WITH THIS!!

Mathematics
2 answers:
NARA [144]4 years ago
8 0
A. $618
multiply 103 x6
suter [353]4 years ago
5 0

Answer:

B.$582

Step-by-step explanation:

100.6= $600 this is the 6 months deposits

3.6=$18 is the bank charged in 6 months

$600-$18=$582

If you analyze and understand the problem you can easily solve it

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Two parallel lines are cut by a transversal as shown below.
svlad2 [7]

Answer:

measure 2 has to be 109 due to the alternate interior angles theorem. Measure 3 has to be 71 due to the supplementary angles theorem.

6 0
4 years ago
Read 2 more answers
We are drawing a 5-card hand from a standard 52-card deck a. What is the probability that all the cards are spades? (5pts)
Solnce55 [7]

Answer:

0.0005 = 0.05% probability that all the cards are spades.

Step-by-step explanation:

The cards are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

52 cards means that N = 52.

13 of the cards are spades, which means that k = 13.

5 card hand means that n = 5.

What is the probability that all the cards are spades?

This is P(X = 5). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 5) = h(5,52,5,13) = \frac{C_{13,5}*C_{39,0}}{C_{52,5}} = 0.0005

0.0005 = 0.05% probability that all the cards are spades.

7 0
3 years ago
What is the length of AA' , rounded to the nearest hundredth? Type a numerical answer is the space provided. Do not type spaces
inna [77]
Coordinate of A are (0,0)
Coordinates of A' are (5,2)

We can find the distance from A to A' using the distance formula:

AA'= \sqrt{(5-0)^{2}+ (2-0)^{2}  } \\  \\ 
AA'= \sqrt{25+4} \\  \\ 
AA'= \sqrt{29} \\  \\ 
AA'=5.39

Thus, rounded to nearest hundredth, AA' is equal to 5.39
3 0
3 years ago
Obtain two numbers such their HCF is 20 and their LCM is 300....... By steps... ​Plzzzzzz answer fast​
kap26 [50]

Answer:

60 and 100

Step-by-step explanation:

Look for 2 multiples of 20 which are also factors of 300.

No long explanation needed

4 0
4 years ago
Help please it’s due today
nata0808 [166]

Answer:

ITS B I WENT THROUGH THIS A YEAR AGO IM IN COLLEGE NOW  MY CAPS ARE BROKEN SO ITS ON CAPS SORRY

Step-by-step explanation:

6 0
3 years ago
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