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4 years ago

3. There are both short term and long term complications of diabetes. Describe an example below for each category

1 answer:

8 0

All I know is that you can get a short-term diabetes when you're pregnant, because my mom had diabetes when she had me and my sister. It comes from the cravings, which for her were salty and very sweet, and sounded very disgusting in my opinion.

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you will need to put your model chromosomes back together for the next part of this activity. the diagram shows how your partner

timurjin [86]

Sister chromatids have different alleles although carry same genes on same loci. So if it doesn't happen so, like if there are same alleles on sister chromatids then there is a problem in its formation. i.e., male and female alleles haven't contributed equally ( may be an error during their segregation process ). And obviously it doesn't happen in a real cell so we must understand this point. Because normally whenever it happens there's one half from the male and one half from the female. (i.e. maternal and paternal alleles contribute equally).

I hope you get the answer!!!

3 0

3 years ago

Scientists can bioengineer skin in a laboratory to treat severe burns and other types of skin injuries. This bioengineered tissu

mrs_skeptik [129]

Answer: The cellular process that enables the cells to grow and develop into tissue is called MITOSIS.

Explanation:

The skin is the largest organ of the body that contains various cells which includes: the epidermal and dermal cells. With the various activities of man, the skin is susceptible to injury through burns.

The healing of the skin, especially injury sustained from burns involves the interaction between the different cell types. Recently, scientists can bioengineer skin in a laboratory to treat severe burns and other types of skin injuries which are grown from living cells.

MITOSIS is the cellular process that enables the cells to grow and develop into tissue. It is also defined as the process by which a cell duplicates into two genetically identical daughter cells.

The process of mitosis occurs in 4 stages; the prophase, metaphase, anaphase, and telophase. The various activities that occurs on these stages brings about the growth and the development of the cells into tissue.

6 0

3 years ago

The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A

ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

Genotype Observed frequency

A → 18 individuals

B → 55 individuals

C → 27 individuals

Do these contradict the genetic model?

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.

Explanation:

Available data:

Crossed genotypes: two
Genotypes among the offspring; Three → A, B, and C
Expected phenotypic ratio → 1:2:1
Total number of individuals, N = 100
A = 18 individuals
B = 55 individuals
C = 27 individuals

So, let us first state the hypothesis:

H₀= the population is equilibrium for this locus → F(A) = 25%, F(B) = 50%, F(C) = 25%
H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 --------------- 25% -------------X = 25 individuals A

2 -------------- 50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

A B C

Observed 18 55 27
Expected 25 50 25
(Obs-Exp)²/Exp 1.96 0.5 0.16

(Obs-Exp)²/Exp

A) (18 - 25)²/25 = 49/25 = 1.96

B) (55 - 50)² / 50 = 25/50 = 0.5

C) (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp

∑ is the sum of the terms
O are the Observed individuals: 2 in chamber B, and 18 in chamber A.
E are the Expected individuals: 10 in each chamber

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99

These results suggest that there is not enough evidence to reject the null hypothesis. We can assume that the locus under study in this population is in equilibrium H-W.

6 0

3 years ago

Which molecule supplies the energy needed to join glucose molecules together to form a molecule of glycogen?

kirill115 [55]

ATP provides the energy to join two glucose molecules together to create glycogen

7 0

3 years ago

Identify the major anatomical areas of long bones

Assoli18 [71]

I think they are, diaphysis, epiphysis, peroiteum, sharpeys fibers, arteries, articular cartliage, and, medullary cavity.

6 0

3 years ago