A 15.0 cm diameter circular loop of wire is placed with the plane of the loop parallel to the uniform magnetic field between the
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Answer:
<em>Both vehicles move east at 3.97 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum </u>
It states that the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is:
P=mv.
If we have a system of two bodies, then the total momentum is the sum of both momentums:
If a collision occurs and the velocities change to v', the final momentum is:
Since the total momentum is conserved, then:
P = P'
Assume both masses stick together after the collision at a common speed v', then:
The common velocity after this situation is:
Assuming east direction to be positive, we have an m1=1459 kg car traveling west at v1=-43 m/s. An m2=9755 kg truck is traveling east at v2=11 m/s. They collide head-on and stick together after that.
Computing the resultant velocity after the collision:
v' = 3.97 m/s
Both vehicles move east at 3.97 m/s
Answer:
the maximum mass suspended to the styrofoam sphere is m = 113.1 kg
Explanation:
The weight due to suspended mass is counterbalanced by the buoyancy force on the sphere
So here we will say
as we know that the maximum buoyancy force that will act on the styrofoam sphere is given as
now from above equation we have
so the maximum mass suspended to the styrofoam sphere is m = 113.1 kg