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Nuetrik [128]
3 years ago
12

A 15.0 cm diameter circular loop of wire is placed with the plane of the loop parallel to the uniform magnetic field between the

pole pieces of a large magnet. When 5.30 A flows in the coil, the torque on it is 0.135 m⋅N. What is the magnetic field strength please?
Physics
1 answer:
velikii [3]3 years ago
6 0

Answer:0.0144 tesla

Explanation:

Magnetic field strength is the same as Magnetomotive force

B= I/2πr

B=magnetic field strength

I=current

r=radius=0.15/2=0.75m

Area=πr2= 1.77m2

torqueT= NIABsin theta

B= T/NIABsin theta

B=0.135/1 * 5.3 * 1.77 *sin90

B=0.0144 tesla

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